转换时间

Question

我有一个脚本

   idea_slug=$_POST['idea_slug'];
   $data['idea_date']=$this->db->query("SELECT * FROM td_idea WHERE idea_slug='$idea_slug'")->result_array();
   $submit_date=$data['idea_date'][0]['idea_submit_date'];

   $datetime1 = DateTime::createFromFormat('d/m/Y', $submit_date);
   $submit_date= $datetime1->format('Y-m-d');

   $submit_date = strtotime($submit_date);

   $end = strtotime('+90 days', $submit_date);

现在我想将$ end转换为Y / m / d格式 我怎么能这样做？

Answer 1

像这样：

echo date('Y/m/d', $end);

Answer 2

DateTime的strtotime()“替代”是modify()。

Answer 3

您可以执行以下操作

$date_format = date('Y/m/d', $end);

Answer 4

$datetime1 = DateTime::createFromFormat('d/m/Y', $submit_date);
$end = clone $datetime1;
$end->add(new DateInterval('P90D'));
echo $end->format('Y/m/d');

Answer 5

这是simpel =），你应该检查DateTime类

$datetime1 = DateTime::createFromFormat('d/m/Y', $submit_date);
$datetime1->modify('+90 day');
$end = $datetime1->format('d/m/Y');

http://php.net/manual/en/datetime.modify.php

http://www.php.net/manual/en/datetime.format.php

干杯