在数据库的所有表中搜索值

时间:2013-07-11 10:27:13

标签: oracle oracle10g find

我需要找到包含Oracle数据库中某些值的表。

我发现了两个问题。我试过的第一个查询:

declare
  l_pattern varchar2(100) := 'По какому вопросу звонили?';
  cursor cf is select table_name,column_name from user_tab_columns where data_type = 'VARCHAR2' order by table_name;

  t_str varchar2(2000) := 'select count(*) from dual where exists( select null from ';
  l_str varchar2(2000); 
  l_where_clause varchar2(2000) := ' where 1=0';
  l_last_table varchar2(100) := '';
  l_cnt number := 0;

  procedure query_ (i_txt varchar2) is
    l_txt varchar2(4000) := i_txt;
    l_ln number := length(l_txt);
    l_pieces number := ceil(l_ln/250);
  begin
   for i in 1..l_pieces loop
      dbms_output.put_line(substr(i_txt, 1+250*(i-1),least(250,l_ln-250*(i-1))));
    end loop;
    dbms_output.new_line;
  end;

begin
  for i in cf loop
    if l_last_table <> i.table_name then
    --  dbms_output.put_line(l_str||l_where_clause);
      execute immediate l_str || l_where_clause ||')' into l_cnt;
      if l_cnt > 0 then 
        query_ ('select * from ' || l_last_table || l_where_clause || ';');
      end if;
      l_cnt := 0;
      l_where_clause := ' where 1=0';
    end if;
    l_last_table := i.table_name;
    l_str := t_str || i.table_name;
    l_where_clause := l_where_clause || ' OR ' || i.column_name || ' like ''' ||l_pattern||'''';
   end loop;
  execute immediate l_str || l_where_clause ||')' into l_cnt;
  if l_cnt > 0 then 
    query_ ('select * from ' || l_last_table || l_where_clause || ';');
  end if;
end;

这会返回错误:

Error starting at line 1 in command:
declare
...
end;

Error report: ORA-06502: PL/SQL: numeric or value error: character
string buffer too small ORA-06512: at line 35
06502. 00000 -  "PL/SQL: numeric or value error%s"
*Cause:    
*Action: 

select * from MV_CATALOG_ITEM where 1=0 OR CODE like 'По какому
вопросу звонили?' OR UUID like 'По какому вопросу звонили?' OR
TITLE like 'По какому вопросу звонили?' OR PARENTITEMUUID like 'По
какому вопросу звонили?' OR CATALOGTITLE like 'По какому  вопросу
звонили?' OR FOLDERTITLE like 'По какому вопросу звонили?' OR
CATALOGUUID like 'По какому вопросу звонили?' OR CATALOGCODE like 'По
какому вопросу звонили?' OR FOLDERUUID like 'По какому вопросу
звонили?';

select * from MV_HIERARCHICAL_TEMPLATES where 1=0 OR STRINGCONTENT2
like 'По какому вопросу звонили?' OR STRINGCONTENT3 like 'По какому
вопросу звонили?' OR IDENTIFIER like 'По какому вопросу звонили?' OR
TEMPLATEUUID like 'По какому вопросу звонили? ' OR ATTRIBUTETITLE like
'По какому вопросу звонили?' OR STRINGCONTENT like 'По какому вопросу
звонили?' OR GROUPTITLE like 'По какому вопросу звонили?' OR INSTUUID
like 'По какому вопросу звонили?' OR OBJUUID like 'По какому вопросу
звонили?' OR TYP ECODE like 'По какому вопросу звонили?' OR GROUPUUID
like 'По какому вопросу звонили?';

我尝试过第二个查询:

select table_name,
       column_name
  from( select table_name,
               column_name,
               to_number(
                 extractvalue(
                   xmltype(
                     dbms_xmlgen.getxml(
                       'select count(*) c from ' || table_name ||
                       ' where to_char(' || column_name || ') = ''JONES'''
                     )
                   ),
                   'ROWSET/ROW/C'
                 )
               ) cnt
          from (select utc.*, rownum
                  from user_tab_columns utc
                 where data_type in ('CHAR', 'VARCHAR2') ) )
 where cnt >= 0

这个返回一个表和列的大列表和错误:

Error starting at line 1 in command: 
select table_name,
...
where cnt >= 0 

Error report:
SQL Error: ORA-19202: Error occurred in XML processing
ORA-00936: missing expression
ORA-06512: at "SYS.DBMS_XMLGEN", line 176
ORA-06512: at line 1
19202. 00000 -  "Error occurred in XML processing%s"
*Cause:    An error occurred when processing the XML function
*Action:   Check the given error message and fix the appropriate problem

我自己找不到办法。

2 个答案:

答案 0 :(得分:4)

谢谢大家!以前的脚本实现得非常慢。 我用这个脚本获得了我的价值:

DECLARE
  match_count integer;
  v_search_string varchar2(4000) := 'advcgtfs000080000ict1mosqiomujrk';

BEGIN  
  FOR t IN (SELECT owner,
                   table_name, 
                   column_name 
              FROM all_tab_columns
             WHERE data_type in ('VARCHAR2') ) 
  LOOP   
    BEGIN
      EXECUTE IMMEDIATE    
        'SELECT COUNT(*) FROM '||t.owner || '.' || t.table_name||
        ' WHERE '||t.column_name||' = :1'   
         INTO match_count  
        USING v_search_string; 
      IF match_count > 0 THEN 
        dbms_output.put_line( t.owner || '.' || t.table_name ||' '||t.column_name||' '||match_count );
      END IF; 
    EXCEPTION
      WHEN others THEN
        dbms_output.put_line( 'Error encountered trying to read ' ||
                              t.column_name || ' from ' || 
                              t.owner || '.' || t.table_name );
    END;
  END LOOP;
END;
/

答案 1 :(得分:2)

您之前发布的代码作为答案(并且由于某种原因没有移到问题中)几乎可以做您想要的相当简单的版本;在这里复制它的主要是次要的,但是一个至关重要的变化:

SET SERVEROUTPUT ON SIZE 100000

DECLARE match_count INTEGER;
    v_owner all_tab_cols.owner%type  := 'NAUCRM';
    v_data_type all_tab_cols.data_type%type :='VARCHAR2';
    v_search_string VARCHAR2(4000) := 'PC_Number';
BEGIN
    FOR t IN (SELECT table_name, column_name
        FROM all_tab_cols
        WHERE owner = v_owner and data_type = v_data_type) LOOP

        EXECUTE IMMEDIATE 'SELECT COUNT(*) FROM '||t.table_name
            ||' WHERE '||t.column_name||' = :1'
       INTO match_count
       USING v_search_string;

       IF match_count > 0 THEN
           dbms_output.put_line( t.table_name ||' '||t.column_name
               ||' '||match_count );
       END IF;
    END LOOP;
END;
/

正如我在评论中已经提到的那样,关键的变化是所有者必须是大写的(除非您的用户构建得非常奇怪!),所以'NAUCRM'而不是'naucrm'