Question

我是SPARQL的初学者，所以如果你能帮助我会很棒。。我有一个像这样的RDF文档：

  @prefix foaf: <http://xmlns.com/foaf/0.1/> .
  @prefix lb:   <http://example.org/lastfm/> .

  lb:bob     foaf:knows      lb:user2, lb:user3, lb:user4 ;
       foaf:age        25 ;
       lb:listenedTo   lb:track1, lb:track2 ;
       lb:topArtist    lb:artist1, lb:artist2 .        

  lb:user2   foaf:knows      lb:user5, lb:user6 ;
       foaf:age        40 ;
       lb:listenedTo   lb:track1, lb:track2, lb:track3 ;  
       lb:topArtist    lb:artist2, lb:artist4 .        

  lb:user3   foaf:knows      lb:user5, lb:bob, lb:user6 ;
       foaf:age        19 ;
       lb:listenedTo   lb:track2, lb:track3, lb:track4 ;
       lb:topArtist    lb:artist2, lb:artist3 .      

  lb:user4   lb:listenedTo   lb:track2, lb:track3, lb:track4 ;
       foaf:age        61 ;
       lb:topArtist    lb:artist3, lb:artist4, lb:artist5 .     

  lb:user5   foaf:knows      lb:user7 ;
       foaf:age        23 ;
       lb:topArtist    lb:artist1, lb:artist3 .

我希望找到所有可以通过lb:bob最多跟随foaf:knows 3次并且至少听过两首曲目的PREFIX rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#> prefix foaf: <http://xmlns.com/foaf/0.1/> prefix lb: <http://example.org/lastfm/> select ?user where { lb:bob foaf:knows | foaf:knows/foaf:knows| foaf:knows/foaf:knows/foaf:knows ?user. ?user lb:listenedTo ?tracks minus{lb:bob lb:listenedTo ?track} filter (?tracks count(*)>=2) }来的用户。我写了一个这样的查询：

Encountered " "count" "count "" at line 12, column 23. Was expecting one of:
 "not" ...
 "in" ...
 <INTEGER_POSITIVE> ...
 <DECIMAL_POSITIVE> ...
 <DOUBLE_POSITIVE> ...
 <INTEGER_NEGATIVE> ...
 <DECIMAL_NEGATIVE> ...
 <DOUBLE_NEGATIVE> ...
 ")" ...
 "=" ...
 "!=" ...
 ">" ...
 "<" ...
 "<=" ...
 ">=" ...
 "||" ...
 "&&" ...
 "+" ...
 "-" ...
 "*" ...
 "/" ...

但是这个错误：

{{1}}

我知道我的查询有很多问题，请你帮我改写一下？

Answer 1

怎么样：

prefix rdf: <http://www.w3.org/1999/02/22-rdf-syntax-ns#>
prefix foaf: <http://xmlns.com/foaf/0.1/>
prefix lb:   <http://example.org/lastfm/>

select ?user
where
{
  lb:bob foaf:knows | foaf:knows/foaf:knows| foaf:knows/foaf:knows/foaf:knows ?user.
  ?user lb:listenedTo ?tracks
}
group by ?user
having (count(?tracks) > 2)

原始查询中有minus我不确定。您是否尝试删除lb:bob作为?user的绑定？ filter (?user != lb:bob)会阻止它。

foaf和计数在sparql 1.1查询中

1 个答案: