Question

我试图从我的电子邮件服务器的SQL数据库中提取联系人。需要提取用户，联系人和所有联系人详细信息。

然而，一切都在一个单独的表中。这就是我正在运行的：

SELECT [Contacts].[ID]
  ,[Users].[LoginName]
  ,[Contacts].[JobTitle]
  ,[Contacts].[Company]
  ,[Contacts].[WebPageAddress]
  ,[Contacts].[FirstName]
  ,[Contacts].[LastName]
  ,[EmailAddresses].[Address]
  ,[EmailAddresses].[Name]
  ,[Addresses].[Name] 
  ,[Addresses].[Address1]
  ,[Addresses].[Town]  
  ,[Addresses].[County]
  ,[Addresses].[Country] 
  ,[Addresses].[Postcode]
  ,[PhoneNumbers].[Name] 
  ,[PhoneNumbers].[Number]


FROM [WorkgroupShare].[dbo].[Contacts]
  INNER JOIN [WorkgroupShare].[dbo].[Users] 
  ON [WorkgroupShare].[dbo].[Contacts].[Owner]=[WorkgroupShare].[dbo].[Users].[ID]
  FULL OUTER JOIN [WorkgroupShare].[dbo].[EmailAddresses]
  ON [WorkgroupShare].[dbo].[Contacts].[ID]= [WorkgroupShare].[dbo].[EmailAddresses].[OwnerID]
  FULL OUTER JOIN [WorkgroupShare].[dbo].[Addresses]
  ON [WorkgroupShare].[dbo].[Contacts].[ID]= [WorkgroupShare].[dbo].[Addresses].[OwnerID]
  FULL OUTER JOIN [WorkgroupShare].[dbo].[PhoneNumbers]
  ON [WorkgroupShare].[dbo].[Contacts].[ID]= [WorkgroupShare].[dbo].[PhoneNumbers].[OwnerID]
  order by [Contacts].[ID]

由于EmailAddress.Name中的Name字段包含Email1或Email2，因此我会为每条记录获得双倍回报。并且Address.Name字段包含业务，家庭或其他我得到三倍。而PhoneNumbers.Name包含4个字段，我得到四倍。然后你将多个联合起来，一个6000个联系人的列表变成几万个。无法弄清楚如何编写循环或while语句。我想我的逻辑只是无法弄清楚语法。任何帮助将不胜感激。

Answer 1

如果在每个“名称”字段中都有一组固定的值，则可以将它们硬编码到列中，这样每个联系人就会得到1行，其中列代表参考数据的每个“风味”。下面的内容（我没有为4个电话号码添加它，因为在这种情况下你没有为Name提供可能的值，但你应该能够得到漂移）：

SELECT [Contacts].[ID]
  ,[Users].[LoginName]
  ,[Contacts].[JobTitle]
  ,[Contacts].[Company]
  ,[Contacts].[WebPageAddress]
  ,[Contacts].[FirstName]
  ,[Contacts].[LastName]
  ,email1.[Address] as email1Address
  ,email2.[Address] as email2Address
  ,Address1.[Address1] as HomeAddress1
  ,Address1.[Town] as HomeAddressTown
  ,Address1.[County] as HomeAddressCounty
  ,Address1.[Country] as HomeAddressCountry
  ,Address1.[Postcode] as HomeAddressPostcode
  ,Address2.[Address1] as BusinessAddress1
  ,Address2.[Town] as BusinessAddressTown
  ,Address2.[County] as BusinessAddressCounty
  ,Address2.[Country] as BusinessAddressCountry
  ,Address2.[Postcode] as BusinessAddressPostcode
  ,Address3.[Address1] as OtherAddress1
  ,Address3.[Town] as OtherAddressTown
  ,Address3.[County] as OtherAddressCounty
  ,Address3.[Country] as OtherAddressCountry
  ,Address3.[Postcode] as OtherAddressPostcode
  ,[PhoneNumbers].[Name] 
  ,[PhoneNumbers].[Number]
FROM [WorkgroupShare].[dbo].[Contacts]
  INNER JOIN [WorkgroupShare].[dbo].[Users] 
  ON [WorkgroupShare].[dbo].[Contacts].[Owner]=[WorkgroupShare].[dbo].[Users].[ID]
  FULL OUTER JOIN [WorkgroupShare].[dbo].[EmailAddresses] email1
  ON [WorkgroupShare].[dbo].[Contacts].[ID]= email1.[OwnerID] AND email1.[Name] = 'Email1'
  FULL OUTER JOIN [WorkgroupShare].[dbo].[EmailAddresses] email2
  ON [WorkgroupShare].[dbo].[Contacts].[ID]= email1.[OwnerID] AND email1.[Name] = 'Email2'
  FULL OUTER JOIN [WorkgroupShare].[dbo].[Addresses] Address1
  ON [WorkgroupShare].[dbo].[Contacts].[ID]= Address1.[OwnerID] AND Address1.Name = 'Home'
  FULL OUTER JOIN [WorkgroupShare].[dbo].[Addresses] Address2
  ON [WorkgroupShare].[dbo].[Contacts].[ID]= Address2.[OwnerID] AND Address2.Name = 'Business'
  FULL OUTER JOIN [WorkgroupShare].[dbo].[Addresses] Address3
  ON [WorkgroupShare].[dbo].[Contacts].[ID]= Address3.[OwnerID] AND Address3.Name = 'Other'
  FULL OUTER JOIN [WorkgroupShare].[dbo].[PhoneNumbers]
  ON [WorkgroupShare].[dbo].[Contacts].[ID]= [WorkgroupShare].[dbo].[PhoneNumbers].[OwnerID]
  order by [Contacts].[ID]

用于从多个表中提取记录的SQL语句

1 个答案: