Question

我有一张桌子主页：

(  
time date,  
qty int  
)

我想创建一个查询，所以每天我得到当天和之前所有日期的数量总和所以这个数据

-----------------------    
time        | qty    
01/09/2009  | 3   
02/09/2009  | 8  
03/09/2009  | 2 
04/09/2009  | 5

我得到：

-----------------------    
time        | total    
01/09/2009  | 3   
02/09/2009  | 11  
03/09/2009  | 13 
04/09/2009  | 18

提前致谢

Answer 1

SELECT TIME, (SELECT SUM(QTY) FROM main m2 WHERE m2.ITME <= mt1.TIME) AS sum  
FROM main m1  
ORDER BY TIME

这应该可以解决问题，尽管它可能不是最快的解决方案。

Answer 2

SELECT
  M.Time,
  SUM(M2.Qty) RunningTotal
FROM
  Main M
  LEFT JOIN Main M2 ON M.Time >= M2.Time
GROUP BY
  M.Time;

Answer 3

这应该会给你一个更快的结果

SELECT time
     , @tot_qty := @tot_qty+qty AS tot_qty
FROM Table1 
JOIN (SELECT @tot_qty := 0) d
order by time