Question

所以我有两个不同的字符串列表;即x和y。

len(y) = len(x) - 1

我想以原始顺序将它们一起添加到一个空字符串中，所以基本上输出= x1 + y1 + x2 + y2 + x3

x = ['AAA','BBB','CCC']
y = ['abab','bcbcb']

#z = ''
z = 'AAAababBBBbcbcbCCC'

如何创建一个for循环来添加到这个空字符串z？

我通常会这样做：

for p,q in zip(x,y):

但由于y小于x，因此不会添加x

的最后一个值

Answer 1

应该这样做：

''.join([item for sublist in zip(x, y+['']) for item in sublist])

Answer 2

你想要itertools.izip_longest。另外，请查看this other post

newStr = ''.join(itertools.chain.from_iterable(
                   itertools.izip_longest(x,y, fillvalue='')
                 ))

Answer 3

您可以使用itertools中的roundrobin recipe：

from itertools import *
def roundrobin(*iterables):
    "roundrobin('ABC', 'D', 'EF') --> A D E B F C"
    # Recipe credited to George Sakkis
    pending = len(iterables)
    nexts = cycle(iter(it).next for it in iterables)
    while pending:
        try:
            for next in nexts:
                yield next()
        except StopIteration:
            pending -= 1
            nexts = cycle(islice(nexts, pending))
x = ['AAA','BBB','CCC']
y = ['abab','bcbcb']
print "".join(roundrobin(x,y))  
#AAAababBBBbcbcbCCC

或者itertools.izip_longest你可以这样做：

>>> from itertools import izip_longest
>>> ''.join([''.join(c) for c in izip_longest(x,y,fillvalue = '')])
'AAAababBBBbcbcbCCC'

Answer 4

from itertools import izip_longest

x = ['AAA','BBB','CCC']
y = ['abab','bcbcb']

unfinished_z = izip_longest( x,y,fillvalue='' ) # an iterator
unfinished_z = [ ''.join( text ) for text in unfinished_z ] # a list
z = ''.join( unfinished_z ) # the string AAAababBBBbcbcbCCC

我更喜欢冗长。

从不同的列表中添加两个不同的值到字符串

4 个答案: