如何substr或strpos这个字符

Question

帮我把这个角色放在一个代码中

1. 4edtee3fdpd0h8o
2. kfz254yae7cw8fb
3. da84s08ifannjs6
4. a4x4c1eaki9ekw1

从这个网址：所有这个$ char

1. httpq：//199.91.153.79/c0l8y769haig/4edtee3fdpd0h8o/1-No%26Batak+%2B+JB.mp3
2. httpq：//199.91.153.63/7otxr1alp53g/kfz254yae7cw8fb/1-Yes%26metalica.mp3
3. httpq：//205.196.120.88/x0xa2u3s6utg/da84s08ifannjs6/1-Yes%26Mirrors.mp3
4. httpq：//205.196.122.248/dv6dyax7o3eg/a4x4c1eaki9ekw1/1-Yes%26reggae.mp3

先谢谢..

Answer 1

你需要这个正则表达式

/httpq:\/\/([\d+]{1,3}[\.|\/])+[^\/]+\/(\S+)\/.*/

示例：

$str = "httpq://199.91.153.63/7otxr1alp53g/kfz254yae7cw8fb/1-Yes%26metalica.mp3";
$regex = "/httpq:\/\/([\d+]{1,3}[\.|\/])+[^\/]+\/(\S+)\/.*/";
echo preg_replace($regex, "$2", $str);