Question

伪代码：

A = [1,2,3,4,5,6,7,8,9]
B = [4,5,6,7,1,2,6,7,8]

count = 0

for i in range(len(A)):
    for j in range(len(B)):
        if A[i:i+3] == B[j:j+3]: #check 3 consecutive numbers if are equal
            count += 1
            print x[i:i+3]
print count

问题：如何在A[4,5,6] == B[4,5,6]时实施，然后跳至A[6,7,8]==B[6,7,8]，而不是A[5,6,7]==B[5,6,7]

Answer 1

您可以使用标志变量：

A = [1,2,3,4,5,6,7,8,9]
B = [4,5,6,7,1,2,6,7,8]

count = 0
skip = False #this is a flag variable

for i in range(len(A)):
    for j in range(len(B)):
        if skip:
            skip = False
            continue
        if A[i:i+3] == B[j:j+3]: #check 3 consecutive numbers if are equal
            count += 1
            print x[i:i+3]
            skip = True 


print count

检查两个列表中的连续编号

1 个答案: