Question

我有已经分组和聚合的数据，看起来像这样：

user    value      count
----    --------  ------
Alice   third      5
Alice   first      11
Alice   second     10
Alice   fourth     2
...
Bob     second     20
Bob     third      18
Bob     first      21
Bob     fourth     8
...

对于每个用户（Alice和Bob），我想要检索他们的前n个值（比方说2），排序的'count'项。所以我想要的输出是：

Alice first 11
Alice second 10
Bob first 21
Bob second 20

我该如何实现？

Answer 1

一种方法是

records = LOAD '/user/nubes/ncdc/micro-tab/top.txt' AS (user:chararray,value:chararray,counter:int);
grpd = GROUP records BY user;

top3 = foreach grpd {
        sorted = order records by counter desc;
        top    = limit sorted 2;
        generate group, flatten(top);
};

输入是：

Alice   third   5 
Alice   first   11 
Alice   second  10
Alice   fourth  2
Bob second  20
Bob third   18
Bob first   21
Bob fourth  8

输出是：

(Alice,Alice,first,11)
(Alice,Alice,second,10
(Bob,Bob,first,21)
(Bob,Bob,second,20)

Answer 2

我刚刚做了一个观察

top    = limit sorted 2;

top是一个内置函数，可能会抛出一个错误，所以我做的唯一一件事是在这种情况下更改了关系的名称，而不是

generate group, flatten(top);

给出了输出

(Alice,Alice,first,11)
(Alice,Alice,second,10
(Bob,Bob,first,21)
(Bob,Bob,second,20)

修改如下所示 -

records = load 'test1.txt' using PigStorage(',') as (user:chararray, value:chararray, count:int);
grpd = GROUP records BY user;
top2 = foreach grpd {
        sorted = order records by count desc;
        top1    = limit sorted 2;
        generate flatten(top1);
};

给了我所需的输出 -

(Alice,first,11)
(Alice,second,10)
(Bob,first,21)
(Bob,second,20)

希望这有帮助。

猪：每组获得前n个值

2 个答案: