如何计算我的自定义论坛的电路板中的回复数量?

时间:2013-07-15 17:21:01

标签: php mysql join

我正在开发一个使用PHP和MySQL的自定义论坛。在这种情况下,我有三个主表:板,线程和消息。我想计算一块板子里的消息数量。 threads表有一个名为“first_msg_id”的列,它是对该线程的第一条消息的引用。我的查询不应该计算此消息。

CREATE TABLE IF NOT EXISTS `forum_messages` (
  `message_id` int(15) NOT NULL AUTO_INCREMENT,
  `thread_id` int(15) NOT NULL,
  `author_id` int(15) NOT NULL,
  `modifier_id` int(15) DEFAULT NULL,
  `content` text NOT NULL,
  `date_posted` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP,
  `date_modified` timestamp NULL DEFAULT NULL,
  PRIMARY KEY (`message_id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1;

CREATE TABLE IF NOT EXISTS `forum_threads` (
  `thread_id` int(15) NOT NULL AUTO_INCREMENT,
  `board_id` int(15) NOT NULL,
  `first_msg_id` int(15) NOT NULL,
  `last_msg_id` int(15) NOT NULL,
  `author_id` int(15) NOT NULL,
  `updater_id` int(15) NOT NULL,
  `title` text NOT NULL,
  `date_posted` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP,
  `date_updated` timestamp NOT NULL DEFAULT '0000-00-00 00:00:00',
  `views` int(15) NOT NULL,
  `status` tinyint(1) NOT NULL,
  `type` tinyint(1) NOT NULL COMMENT '0 normal, 1 sticky, 2 global.',
  PRIMARY KEY (`thread_id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1;

CREATE TABLE IF NOT EXISTS `forum_boards` (
  `board_id` int(15) NOT NULL AUTO_INCREMENT,
  `parent_id` int(15) NOT NULL,
  `category_id` int(15) NOT NULL,
  `last_msg_id` int(15) NOT NULL,
  `position` tinyint(1) NOT NULL,
  `title` text NOT NULL,
  `description` text NOT NULL,
  `status` tinyint(1) NOT NULL,
  `thread_count` int(15) NOT NULL,
  `reply_count` int(15) NOT NULL,
  PRIMARY KEY (`board_id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1;

这是我的查询:

$query_board_replies = "
                    SELECT
                        m.message_id, m.thread_id,
                        t.thread_id, t.first_msg_id, t.board_id
                    FROM forum_messages AS m
                    LEFT JOIN forum_threads AS t ON t.first_msg_id != m.message_id
                    WHERE t.board_id = ".$board_id."
                    ORDER BY m.message_id";

它不会返回任何错误,但它会给我一个完全错误的计数。只有两个实际的回复,但它在特定的董事会中返回了18个。

有什么想法吗?

1 个答案:

答案 0 :(得分:0)

这应该这样做。

$query = "
  SELECT
    COUNT(*)
  FROM
    forum_messages A,
    forum_threads  B
  WHERE
    A.thread_id   = B.thread_id    AND
    A.message_id != B.first_msg_id AND
    B.board_id    = " . mysqli_real_escape_string($dbc, $board_id) . "
";
$rs = mysqli_query($dbc, $query);
list($count) = mysqli_fetch_array($rs);
echo $count;
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