Question

如果您获得包含以下内容的.txt file：

James Doe 2/16/96 IT210 A BUS222 B PHY100 C
John Gates 4/17/95 IT101 C MATH112 B CHEM123 A
Butch Thomas 1/28/95 CS100 C MATH115 C CHEM123 B

你怎么能得到它所以它需要类名和等级并将它们放入一个空字典而忽略其余的？我已将代码设置为读取.txt file，但卡住了。有什么建议吗？

这是我打开文件的代码：

def readFile():
    new_dict = {}
    myFile = open('Students.txt', 'r')
    for line in myFile:

Answer 1

为什么不使用词典列表而不是为每个学生制作不同的变量？

请参阅以下代码：

>>> dictList = []
>>> with open('Students.txt', 'r') as f:
        for line in f:
            elements = line.rstrip().split(" ")[3:]
            dictList.append(dict(zip(elements[::2], elements[1::2])))       
>>> dictList
[{'IT210': 'A', 'PHY100': 'C', 'BUS222': 'B'}, {'IT101': 'C', 'MATH112': 'B', 'CHEM123': 'A'}, {'CS100': 'C', 'CHEM123': 'B', 'MATH115': 'C'}]

如果您希望维护字典中txt文件中给出的顺序，请查看OrderedDict。

Answer 2

豆：

def readFile():
    new_dict = {}
    myFile = open('Students.txt', 'r')
    for line in myFile:
        line2=line.split()
        class1=line2[3]
        gra=line2[4]
        new_dict[class1]=gra

Answer 3

li = []
with open("file.txt", 'r') as f:
    line = f.readline().split()
    while line:
        dict = {}
        dict[line[-6]] = line[-5]
        dict[line[-4]] = line[-3]
        dict[line[-2]] = line[-1]
        li.append(dict)
        line = f.readline().split()

li = [{'IT210': 'A', 'PHY100': 'C', 'BUS222': 'B'}, {'IT101': 'C', 'MATH112': 'B', 'CHEM123': 'A'}, {'CS100': 'C', 'CHEM123': 'B', 'MATH115': 'C'}]

Answer 4

以下代码可以满足您的需求。

import re

student = 'James Doe 2/16/96  IT210 A BUS222 B PHY100 C'
pattern = '([0-9]{1,2}/[0-9]{1,2}/[0-9]{1,2})'
end = re.search(pattern, student).end()
found = student[end+2:]
x = found.split(' ')
numberOfEntries = len(x) / 2
i = 0
Dict = {}

while i < numberOfEntries:
    Dict[x[i]] = x[i+1]
    i = i + 1

print Dict

Answer 5

dic={}
for line in myFile:
   info=line.split(' ')
   firstname=info[0]
   lastname=info[1]
   firstClass=info[3]
   firstgrade=info[4]
   secondClass=info[5]
   secondgrade=info[6]
   thirdClass=info[7]
   thirdGrade=info[8]
   gradeInfo={firstClass:firstgrade,secondClass:secondgrade,thirdClass:thirdgrade}
   name='%s %s' %(firstname,lastname)
   dic+={name,gradeInfo}

Answer 6

student_dict = {}
for line in open('input','r'):
    line2=line.split()
    name = ' '.join(line2[0:2])
    grades = line2[3:]
    grades_dict = {grades[i]:grades[i+1] for i in xrange(0,len(grades),2)}
    student_dict[name]=grades_dict

给出：

>>> student_dict
{'James Doe': {'IT210': 'A', 'PHY100': 'C', 'BUS222': 'B'}, 'Butch Thomas': {'CS100': 'C', 'CHEM123': 'B', 'MATH115': 'C'}, 'John Gates': {'IT101': 'C', 'MATH112': 'B', 'CHEM123': 'A'}}

使用Python从.txt文件创建字典

6 个答案: