Question

我希望select每天p_amount Payments p_date @startdate @enddate CREATE TABLE [dbo].[tbl_Payments]( [p_id] [bigint] IDENTITY(100000,1) NOT NULL, [p_amount] [int] NOT NULL, [p_status] [tinyint] NOT NULL, [p_date] [datetime] NOT NULL, [p_creditor] [int] NOT NULL, [p_debtor] [int] NOT NULL, [p_type] [int] NOT NULL, CONSTRAINT [PK_tbl_Payments] PRIMARY KEY CLUSTERED ) sum day --------------------------------- 30 2013-07-01 40 2013-07-02 ... .... 10 2013-07-19 {{1}}

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我想跟随

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Answer 1

我不熟悉sql-server查询，但你问题的查询是像这样的东西

SELECT    sum(p_amount) as sum, CONVERT(date, getdate()) as day
FROM      [YourTable]
WHERE     [YourDate] BETWEEN [day1] AND [day2] group by day

Answer 2

尝试

SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, p_date)) [date],
       SUM(p_amount) [sum]
  FROM tbl_Payments
 WHERE DATEADD(dd, 0, DATEDIFF(dd, 0, p_date)) BETWEEN '20130701' AND '20130731'
 GROUP BY DATEADD(dd, 0, DATEDIFF(dd, 0, p_date))

示例输出：

|                        DATE | SUM |
-------------------------------------
| July, 01 2013 00:00:00+0000 |  22 |
| July, 02 2013 00:00:00+0000 |  30 |
| July, 03 2013 00:00:00+0000 |  35 |

这是 SQLFiddle 演示

选择两个日期之间的列的总和

2 个答案: