Question

我有一个.NET应用程序，它利用.NET Regex功能来匹配EPL标签文本字符串。通常我会使用以下内容： ^ [A-Z0-9，] +“（。+）”$ ，它将匹配每一行（它捕获epl代码之间的文本）。然而，最近EPL发生了变化，并且在每个EPL行的末尾都有换行符 \ x0D \ x0A 。

所以我将代码模式更改为 [（（\ r \ n）|（\ x0D \ x0A））A-Z0-9，] +“（。+）” 而现在它只会把放在儿童接触不到的地方并且不承认休息。

如何匹配epl代码之间的文本？

这是我想要匹配的原始EPL

N 0D0A A230,1,0,2,1,1，N，“勿让儿童接触”0D0A A133,26,0,4,1,1，N，“FUROSEMIDE TABLETS 40 MG”0D0A A133,51,0,4,1,1，N，“一个人在早上”0D0A A133,76,0,4,1,1，N “” 0D0A A133,101,0,4,1,1，N “” 0D0A A133,126,0,4,1,1，N “” 0D0A A133,151,0,4,1,1，N “” 0D0A A133,176,0,4,1,1，N，“19/04/13 28 TABLET（S）”0D0A A133,201,0,4,1,1，N，“ELIZABETH M SMITH”0D0A LO133,232,550,40D0A A133,242,0,2,1,1，N，“任何医疗中心，蓝色路”0D0A A133,260,0,2,1,1，N，“DN54 5TZ，电话：01424 503901”0D0A P1

Answer 1

我认为您正在寻找RegexOptions.Multiline选项。如：

Regex myEx = new Regex("^[A-Z0-9,]+\".+?\"$", RegexOptions.Multiline);

实际上，正则表达式应为：

"^[A-Z0-9,]+\".*\"\r?$"

Multiline查找换行符\n。但该文件包含\r\n。所以它找到结束引用，看到$，并查找换行符。但该文件具有Windows行结尾（\r\n）。我修改过的正则表达式跳过该字符，如果它在那里。

如果要在结果中删除这些字符，请创建一个捕获组：

"^([A-Z0-9,]+\".*\")\r?$"

或者，您可以通过在每个结果上调用Trim来过滤它们：

MatchCollection matches = myEx.Matches(text);
foreach (Match m in matches)
{
    string s = m.Value.Trim();  // removes trailing \r
}

Answer 2

谢谢Jim，我尝试了你的建议并且有效......

我使用了以下内容......

Dim sText As String = "N 0D0A A230,1,0,2,1,1,N,"Keep out of the reach of children"0D0A A133,26,0,4,1,1,N," FUROSEMIDE TABLETS 40 MG"0D0A A133,51,0,4,1,1,N," ONE IN THE MORNING"0D0A A133,76,0,4,1,1,N,""0D0A A133,101,0,4,1,1,N,""0D0A A133,126,0,4,1,1,N,""0D0A A133,151,0,4,1,1,N,""0D0A A133,176,0,4,1,1,N,"19/04/13 28 TABLET(S)"0D0A A133,201,0,4,1,1,N,"ELIZABETH M SMITH"0D0A LO133,232,550,40D0A A133,242,0,2,1,1,N,"Any Medical Centre,Blue Road"0D0A A133,260,0,2,1,1,N,"CN54 1TZ,Tel:01424 503901"0D0A P1"
Dim sRet As String = String.Empty
Dim sTemp As String = String.Empty
Dim m As Match
Dim grp As System.Text.RegularExpressions.Group

Dim sPattern As String = "^([A-Z0-9,])+\"".*\""\r?$"
Dim sPatternRegex As New Regex(sPattern, RegexOptions.Multiline)
Dim matches As MatchCollection = sPatternRegex.Matches(sText)

For Each m In matches
   ' removes trailing \r
   'Dim s As String = m.Value.Trim()
    sTemp += m.Value.Trim() + vbCrLf
Next

' The previous code detects where the line feeds are, replaces the old one with a standard vbCrLF, then the following code parses it like normal

sPattern = "^[A-Z0-9,]+\""(.+)\""$" 

' Standard WinPrint EPL Label: The parsed version would appear as: ^[A-Z0-9,]+\"(.+)\"$

For Each s As String In sTemp.Split(vbCrLf)
   m = Regex.Match(s.Trim, sPattern)
   grp = m.Groups(1)
   sRet += grp.Value + vbCrLf
Next

Return sRet.Trim

为什么.NET多行正则表达式中的^ $与CRLF 0D0A不匹配？

2 个答案: