Question

我有一个getJSON（）调用，用于访问返回某些数据的视图。该调用有效并且数据被检索但是尽管如此，我仍然会收到500错误。

Failed to load resource: the server responded with a status of 500 (INTERNAL SERVER ERROR)

MultiValueDictKeyError at /album_ajax/
"Key u'reid' not found in <QueryDict: {}>"

Request Method: GET
Request URL: http://127.0.0.1:8000/album_ajax/
Django Version: 1.4.3
Python Executable: /usr/bin/python
Python Version: 2.7.1
Python Path: ['/Users/Santi/programming/feastfm', '/Library/Python/2.7/site-packages/pip-1.2.1-py2.7.egg', '/Library/Python/2.7/site-packages/South-0.7.6-py2.7.egg', '/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python27.zip', '/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7', '/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/plat-darwin', '/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/plat-mac', '/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/plat-mac/lib-scriptpackages', '/System/Library/Frameworks/Python.framework/Versions/2.7/Extras/lib/python', '/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/lib-tk', '/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/lib-old', '/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/lib-dynload', '/System/Library/Frameworks/Python.framework/Versions/2.7/Extras/lib/python/PyObjC', '/Library/Python/2.7/site-packages']

我看过SO并试图询问IRC，但一直无法弄清楚为什么我会收到此错误。 view / call的语法直接从：http://lethain.com/two-faced-django-part-5-jquery-ajax/

复制

views.py

def get_album_tracks(request):
    get = request.GET.copy()
    reid = get["reid"]
    url = "http://www.musicbrainz.org/ws/2/release/"+reid+"?fmt=json&inc=artist-credits+recordings"
    data = urllib2.urlopen(url)
    api_results = json.load(data)
    tracks = []
    for entry in api_results['media']:
        for track in entry['tracks']:
            artist = track['artist-credit'][0]['name']
            title = track['title']
            tracks.append({'artist':artist, 'title':title})
    # results = {'reid':reid, 'tracks':tracks}
    results = {'test':"is this working?", "reid":reid, 'tracks':tracks}
    return_json = simplejson.dumps(results)
    return HttpResponse(return_json, mimetype='application/json')

getJSON（）调用

$.getJSON("/album_ajax/", {"reid": reid}, function(json){
        if(json['tracks']){
            //alert("json?: " + json["tracks"]+" reid: "+json['reid']);
            // var album = $('data-reid ='+)
            for(var i=0; i<json['tracks'].length; i++){
                //console.log(json['tracks'][i]['title'])
                var artist = json['tracks'][i]['artist']
                var title = json['tracks'][i]['title']
                $(ul).append("<li class = 'album-track track' data-artist = '"+escape(artist) +"' data-title ='" + escape(title) +"'>"+artist +" - "+ title+"</li>");
            }

        }
        else{
            alert('no results')
        }
        })

我不明白为什么我得到500错误并且运行成功功能。

修改

我在我的视图中放置了一个print语句，看起来视图函数被调用了两次，一次是空的QueryDict，一次是一个包含reid变量的QueryDict：

album_tracks was just called
<QueryDict: {}>
album_tracks was just called
<QueryDict: {u'reid': [u'0447570d-4804-49f1-9396-d71ddd8f59c4']}>

我仍然不确定代码在哪里进行两次调用。

编辑2

包括具有getJSON（）调用的整个函数

$('.album').click(function(e){
    var $target = $(e.target);
    // if(!$target.is("ul"))
    if(!$target.is("div")) //magic happens here!!
        {
            return;
        }
    if($(this).children("li").length >= 1){
        $(this).children("li").toggle();
    }
    else{
        var reid = $(this).data('reid');
        ul = this;
        var data = {"reid": reid};
        // var args = { type:"GET", url:"/album/", data:data, complete:done };
        // $.ajax(args);
        $.getJSON("/album_ajax/", data, function(json){
        if(json['tracks']){
            //alert("json?: " + json["tracks"]+" reid: "+json['reid']);
            // var album = $('data-reid ='+)
            for(var i=0; i<json['tracks'].length; i++){
                //console.log(json['tracks'][i]['title'])
                var artist = json['tracks'][i]['artist']
                var title = json['tracks'][i]['title']
                $(ul).append("<li class = 'album-track track' data-artist = '"+escape(artist) +"' data-title ='" + escape(title) +"'>"+artist +" - "+ title+"</li>");
            }

        }


        else{
            alert('no results')
        }
        })
    }
});

Answer 1

事实证明我在课堂上有多个元素，其中一个元素具有使ajax调用工作所需的数据属性，另一个没有。他们都在开火，一人失败而另一人失败。

感谢@ jesse-vogt告诉我在html代码中查找.album类。

getJSON调用成功但仍然抛出500错误

1 个答案: