Question

我的目标是实现如下结果集

CODE | TOTAL1 | TOTAL2  
1    | 56     | 34  
2    | 12     | 15  
3    | 90     | 3

有2个表，例如tableA和tableB
tableB.type

的计数不同

SELECT   code, COUNT (*) AS total1  
FROM tableA a
WHERE a.ID IN (select ID from tableB
    where type = 'XYZ')
GROUP BY code


SELECT   code, COUNT (*) AS total2  
FROM tableA a
WHERE a.ID IN (select ID from tableB
    where type = 'ABC')
GROUP BY code

我想在同一个查询中显示每种类型的每个代码的计数

提前致谢

Answer 1

没有子查询

SELECT a.code,
sum(decode(b.type,'ABC',1,0)) AS total1,sum(decode(b.type,'XYZ',1,0)) AS total2
FROM tableA a
join tableB b on a.ID = b.ID
GROUP BY a.code

问候
ķ

Answer 2

子查询：

SELECT   code, (select COUNT (*) AS total1  
FROM tableA a1
WHERE a.ID IN (select ID from tableB
    where type = 'XYZ')
    and a1.code = tableA.code) as Total1,  
(select COUNT (*) AS total2  
FROM tableA a2
WHERE a.ID IN (select ID from tableB
    where type = 'ABC')
    and a2.code = tableA.code) as Total2)
from tableA
group by Code

Answer 3

可能其中许多方法之一是在内联视图中将两者联合起来，然后选择计数总和，如下所示：

SELECT代码，SUM（total1）total1，SUM（total2）total2 FROM （ SELECT代码，COUNT（）total1,0 total2 来自tableA a 在哪里a.ID IN（从tableB中选择ID 其中type ='XYZ'） GROUP BY代码联盟 SELECT代码，0，COUNT（）
来自tableA a 在哪里a.ID IN（从tableB中选择ID 其中type ='ABC'） GROUP BY代码） GROUP BY代码;

一个查询中的不同记录计数值

3 个答案: