Question

我正在尝试为每个位置找到特定用户的最后一个条目。我还需要忽略余额为零的任何行。

样本表：

    ID location user balance
    -- -------- ---- -------
     1 GLA      A    10.21
     2 GLA      A    0.00
     3 GLA      B    45.68
     4 GLA      B    12.56
     5 EDI      C    1.23
     6 EDI      D    5.48
     7 EDI      D    0.00
     8 LON      E    78.59
     9 MAN      F    0.00
    10 MAN      F    12.98
    11 MAN      G    56.45
    12 MAN      G    89.25
    13 MAN      H    0.00
    14 BIR      I    0.00
    15 BIR      I    32.87

需要的结果：

    ID location user balance
    -- -------- ---- -------
     4 GLA      B    12.56
     5 EDI      C    1.23
     8 LON      E    78.59
    10 MAN      F    12.98
    12 MAN      G    89.25
    15 BIR      I    32.87

我只能为一位生病的同事辩护，不幸的是我的SQL知识相对有限。

我一直在研究使用MAX和PARTITION BY但到目前为止没有运气。这适用于SQL Server 2005数据库。

对此的任何帮助将不胜感激。我将添加任何进展。

非常感谢。

Answer 1

Select   
      A.ID ,
      A.location,
      A.[user] ,
      A.balance from TABLE1 A 
     inner join (
                 Select Max(Id) AS Id from TABLE1 
                 group by location,[user]
                 ) B 
      on A.ID=B.ID 
      WHERE A.Balance>0

Sql Fiddle Demo

Answer 2

您应该可以使用row_number()来获得结果：

select id, location, [user], balance
from 
(
  select id, location, [user], balance,
    row_number() over(partition by location, [user]
                        order by id desc) seq
  from yourtable
) d
where seq = 1
  and balance <> 0
order by id;

请参阅SQL Fiddle with Demo

Answer 3

使用Row_Number()功能：

SELECT id,
   location,
   user,
   balance
FROM   ( SELECT ROW_NUMBER( )
              OVER (
                PARTITION BY user
                ORDER BY id DESC ) AS rowid,
            *
     FROM   tableA ) AS data
WHERE  ( rowid = 1 )
   AND ( balance > 0 )

查找特定用户ID的最后一个条目

3 个答案: