Question

我使用apache commons文件上传来上传servlet上的文件。但在解析请求后，我总是得到文件项的空列表。我的代码如下所示：

if (!ServletFileUpload.isMultipartContent(request)) {
    throw new UnsupportedOperationException("Expected `multipart/...` content-type header ");
}

ServletFileUpload upload = new ServletFileUpload(new DiskFileItemFactory());

List<FileItem> items = upload.parseRequest(request);

logger.debug("Items size: " + items.size());

哪里有问题？请求发送正确

Answer 1

在表单操作中添加enctype =“multipart / form-data”

<form action="UploadServlet" method="post"
                          enctype="multipart/form-data"> 

 </form>



 DiskFileItemFactory factory = new DiskFileItemFactory();
 // maximum size that will be stored in memory
 factory.setSizeThreshold(maxMemSize);
 // Location to save data that is larger than maxMemSize.
 factory.setRepository(new File("c:\\temp"));

 // Create a new file upload handler
 ServletFileUpload upload = new ServletFileUpload(factory);
 // maximum file size to be uploaded.
 upload.setSizeMax( maxFileSize );

 try{ 
         // Parse the request to get file items.
         List fileItems = upload.parseRequest(request);

 }catch(Exception e){

 }

http://www.tutorialspoint.com/servlets/servlets-file-uploading.htm

Answer 2

创建DiskFileItemDirectory时，请使用此构造函数

DiskFileItemFactory factory = new DiskFileItemFactory(FILE_SIZE, new File("/yourfolder"));

FILE_SIZE是您允许上传的最大文件大小。确保您对“/ yourfolder”中的文件夹位置有权限（更改此内容...）

Commons FileUpload。空项目列表

2 个答案: