组合来自同一来源的两个计数查询

时间:2013-08-07 04:06:57

标签: mysql database

我有两个查询返回带有计数的服务项列表。一个用于整个数据库,另一个用于指定的时间段。它们单独运行很好,但我想将它们优化为单个查询。

这两个查询是:

SELECT service_type, count(service_type) from qba_customers group by service_type order by count(service_type) desc

SELECT service_type, count(service_type) from qba_customers WHERE created_on BETWEEN '2013-01-01' AND '2013-06-30' group by service_type order by count(service_type) desc

我尝试了一些不成功的事情,下面是我认为最初会起作用的事情:

SELECT service_type, COUNT(service_type) AS full_count, (count(service_type) WHERE created_on BETWEEN '2013-01-01' AND '2013-06-30') AS period_count FROM qba_customers GROUP BY service_type ORDER BY service_type DESC

提前致谢!

2 个答案:

答案 0 :(得分:0)

所有聚合函数(包括COUNT)仅包含一个值,如果它不是NULL。要仅计算日期范围内的行,请使用CASE构造作为count参数。如果CASE返回一个值,则计算它。如果它没有返回值,则不计算:

SELECT
  service_type,
  COUNT(service_type) AS GrandTotal,
  COUNT(CASE WHEN created_on BETWEEN '2013-01-01' AND '2013-06-30' THEN 1 END) AS FirstHalf2013
FROM qba_customers
GROUP BY service_type
ORDER BY GrandTotal

对于FirstHalf2013列,如果created_on在目标范围内,则CASE返回非空值(我在此使用1,但它可以是任何非空值)。如果created_on不在目标范围内,则CASE会返回NULL,这意味着该行不会被计算在内。

答案 1 :(得分:0)

使用case语句尝试:

SELECT service_type, 
       count(service_type) as full_count,
       sum(case when created_on between '2013-01-01' and '2013-06-30' then 1 else 0 end) as period_count 
  FROM qba_customers 
 GROUP by service_type
 ORDER by service_type desc
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