Question

我正在使用jquery-2.0.3.min.js，bootstrap.min.js，jquery-ui-1.10.3.min.js，DataTables-1.9.4 with tabletools，datatables.net / blog / Twitter_Bootstrap_2 < / p>

我的观点

  <div id="windowDepartment" title="Departments"></div>


 <table cellpadding="0" cellspacing="0" border="0" class="table table-striped table-bordered table-hover table-condensed" id="DepartmentTable">
        <thead>
            <tr>
                <th>departmentID</th>
                <th>departmentName</th>
                <th>description</th>
                <th>Action</th>
            </tr>
        </thead>
        <tbody>
        </tbody>
    </table>

数据表初始化脚本

    $(document).ready(function () {
    oDepartmentTable = $('#DepartmentTable').dataTable(
            {

                "sDom": "T<'clear'>lfrtip",
                "bJQueryUI": true,
                "sPaginationType": "full_numbers",
                "bServerSide": true,
                "sAjaxSource": "Department/AjaxList",
                "aaSorting": [[2, 'asc'], [3, 'asc']],
                "aoColumns": [
                                { "mDataProp": "departmentID", "sType": "string", "bVisible": false, "bSearchable": false },
                                { "mDataProp": "departmentName", "sType": "string", "bVisible": true, "bSearchable": true },
                                { "mDataProp": "description", "sType": "string", "bVisible": true, "bSearchable": true },
                                { "mDataProp": null,"bSearchable": false,
                                 "sDefaultContent": '<div class="btn-group"><a class="btn btn-mini dropdown-toggle" data-toggle="dropdown" href="#"><span class="icon-circle-arrow-down"></span></a><ul class="dropdown-menu"><li><a class="editDepartment"> <i class="icon-pencil"></i> Edit</a></li><li><a class="deleteDepartment"> <i class="icon-trash"></i> Delete</a></li></ul></div>'
                                }
                            ],

                "oTableTools": {
                    "sSwfPath": "/Content/DataTables-1.9.4/extras/TableTools/media/swf/copy_csv_xls_pdf.swf"
                }

            });

        });

编辑表格脚本

       $(document).ready(function () {
            $('#DepartmentTable tbody').on('click', 'a.editDepartment', function (e) {
                e.preventDefault();

                //1. Dose not work shows "not available"
                var aData = oDepartmentTable.fnGetData(this)

                //2. Gets the correct ID if "bVisilble=true"
                var departmentid = $(this).parent().parent().parent().parent().parent().children()[0].innerHTML ;

                //goto Edit Controller. DepartmentID is required here  
                $.get('Department/Edit/' + departmentid , function (data) {
                    $('div#windowDepartment').html(data);

                    //Open Dialog box 
                    $("#windowDepartment").dialog().dialog({
                        resizable: true,
                        height: 500,
                        width: 500,
                        modal: true,
                        buttons:
                    {
                        Edit: function () {
                            editDepartment();   //Saves the data. Works fine
                        }, // end ok button

                        Cancel: function () {
                            $(this).dialog("close");
                        }
                    },  //end buttons
                        close: function () {
                            $(this).dialog("close");
                        }
                    }); //end modal edit
                });
            });
        });

我的问题。（在EDIT FORM SCRIPT中）

我需要将DepartmentID传递给我的控制器（'Department / Edit /'+ departmentid）

我的观察 1）var aData = oDepartmentTable.fnGetData(this)始终在chrome控制台中显示“不可用”。

2）var departmentid = $(this).parent().parent().parent().parent().parent().children()[0].innerHTML获取正确的departmentID，如果我使用“bVisible”：在数据表初始化时为true。

（3）我不想向最终用户显示departmentID。如果我做“bVisible”：在数据表初始化时为假，那么

var departmentid = $(this).parent().parent().parent().parent().parent().children()[0].innerHTML返回departmentName

谢谢

Answer 1

查看数据表论坛here和fnGetPosition

中的讨论

请尝试使用此clickhandler：

$(document).ready(function () {
    $('#DepartmentTable tbody tr').on('click', function (e) {

        // get the position of the current data from the node
        var aPos = oDepartmentTable.fnGetPosition( this );

        // get the data array
        var aData = oDepartmentTable.fnGetData( aPos[0] );

        // get departmentID for the row
        var departmentID = aData[aPos].departmentID;
        console.log(departmentID);

        // ... do your stuff here, eg
        //goto Edit Controller. DepartmentID is required here  
        //$.get('Department/Edit/' + departmentid , function (data) {
        //..
        //..
    });
});

它对我有用。然而，并不像文档所说的那样。另外，我首先试用了数据表1.9.1 - 它根本没用。猜猜这个数据区的区域有一些错误，并且已经在版本上进行了重构。

如何在datatable中获取选定的Table单元格值

1 个答案: