我不知道我做错了什么,但所有项目都应该在标记<li>
项目</li>
内,但只有第一项是什么,可以是什么?
的javascript:
$.getJSON("http://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20xml%20where%20url%3D'http%3A%2F%2Frss.cnn.com%2Fservices%2Fpodcasting%2Fac360%2Frss.xml'%20AND%20itemPath%3D%22%2F%2Fchannel%22&format=json&diagnostics=true&callback=?", function (data) {
var titles = data.query.results.channel.item.map(function(item) {
return item.title;
});
$(".container-list-podcast ul").append('<li>' + titles.join('</li>'));
});
答案 0 :(得分:4)
这一行必须是:
$(".container-list-podcast ul").append('<li>' + titles.join('<li>'));
编辑以符合T.J Crowder的建议。
答案 1 :(得分:3)
您没有后续打开的<li>
代码。你可能意味着:
$(".container-list-podcast ul").append('<li>' + titles.join('</li><li>') + '</li>');
// This opens the first item (only) ----^ ^ ^ ^
// This closes each item except the last --------------------+ | |
// This opens the second one onward ------------------------------+ |
// This closes the last one ------------------------------------------------+
或者,如果您想依赖关闭</li>
代码为optional这一事实,可能是:
$(".container-list-podcast ul").append('<li>' + titles.join('<li>'));
答案 2 :(得分:0)
更新了代码http://jsfiddle.net/m627u/:
$.getJSON("http://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20xml%20where%20url%3D'http%3A%2F%2Frss.cnn.com%2Fservices%2Fpodcasting%2Fac360%2Frss.xml'%20AND%20itemPath%3D%22%2F%2Fchannel%22&format=json&diagnostics=true&callback=?", function (data) {
var titles = data.query.results.channel.item.map(function(item) {
return '<li>'+item.title+'</li>';
});
$(".container-list-podcast ul").append(titles);
});
您将集体字符串放入<li>
,而不是每个标题。
答案 3 :(得分:0)
$.getJSON("http://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20xml%20where%20url%3D'http%3A%2F%2Frss.cnn.com%2Fservices%2Fpodcasting%2Fac360%2Frss.xml'%20AND%20itemPath%3D%22%2F%2Fchannel%22&format=json&diagnostics=true&callback=?", function (data) {
var titles = data.query.results.channel.item.map(function(item) {
return item.title;
});
$.each(titles, function(key, value){
$(".container-list-podcast ul").append('<li>' + value + '</li>');
});
});
答案 4 :(得分:0)
这是工作DEMO
$.getJSON("http://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20xml%20where%20url%3D'http%3A%2F%2Frss.cnn.com%2Fservices%2Fpodcasting%2Fac360%2Frss.xml'%20AND%20itemPath%3D%22%2F%2Fchannel%22&format=json&diagnostics=true&callback=?", function (data) {
var titles = data.query.results.channel.item.map(function(item) {
return item.title;
});
$(".container-list-podcast ul").append('<li>' + titles.join('</li><li>'));
});
答案 5 :(得分:0)
这是解决方案的修改代码http://jsfiddle.net/Cf5QU/2/。
$.getJSON("http://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20xml%20where%20url%3D'http%3A%2F%2Frss.cnn.com%2Fservices%2Fpodcasting%2Fac360%2Frss.xml'%20AND%20itemPath%3D%22%2F%2Fchannel%22&format=json&diagnostics=true&callback=?", function (data) {
var titles = data.query.results.channel.item.map(function(item) {
return item.title;
});
$(".container-list-podcast ul").html('<li>' + titles.join('</li>' + '<br>' + '<li>'));
});
你必须添加break line和new li