Question

我目前正在撰写冒险游戏创建者框架，到目前为止我有以下课程：

// Base class that represents a single episode from a complete game.
public abstract class Episode : IEpisode
{
    public RoomList Rooms {get; }
    public ArtefactList Artefacts {get; }

    public Episode()
    {
        Rooms = new RoomList();
        Artefacts = new ArtefactList();
    }
}

// This is a list of all objects in the episode.
public ArtefactList : List<IArtefact>
{
    public IArtefact Create( UInt32 id, String text )
    {
        IArtefact art = new Artefact( id, text );

        base.Add( art );

        return art;
    }
}

// This is a list of all rooms in the episode.
public RoomList : List<IRoom> 
{   
    public IRoom Create( UInt32 id, String text )
    {
        IRoom rm = new Room( id, text );

        base.Add( rm );

        return rm;
    }
}

public class Room : IRoom
{
    public UInt32 Id { get; set; }
    public String Text { get; set; }

    public IList<IArtefact> Artefacts
    {
        get
        {
            return ???what??? // How do I access the Artefacts property from
                                // the base class:
                                //  (Room --> RoomList --> Episode)
        }
    }   
}

public class Artefact : IArtefact
{
    public UInt32 Id { get; set; }
    public String Text { get; set; }
    public IRoom CurrentRoom { get; set; }

}

public interface IArtefact
{
    UInt32 Id { get; set; }
    String Text { get; set; }
    IRoom CurrentRoom { get; set; }
}

public interface IRoom
{
    UInt32 Id { get; set; }
    String Text { get; set; }
    IList<IArtefact> Artefacts {get; }
}

我想知道的是Room类应该如何访问Artefacts类的封装Episode属性，而不必将引用传递给Episode所有沿着对象图的方式，即Episode - ＆gt; RoomsList - ＆gt; Room。

Answer 1

房间和人工制品之间存在一对多的关系。因此，您必须在RoomList.Create方法中初始化此关系：

public IRoom Create( UInt32 id, String text , ArtefactList artefacts)
{
    IRoom rm = new Room( id, text , artefacts);
    base.Add( rm );
    return rm;
}

创建房间时，您可以这样做：

var episode = new Episode();
episode.Rooms.Create(1, "RoomText", episode.Artefacts);

你应该对ArtefactList.Create做同样的事情，因为Artefact需要IRoom实例。

访问对象图中的根类封装属性

1 个答案: