Question

您好我需要有关MySQL数据库查询的帮助。

我有一个看起来像这样的表：

ID  TRACKID         DATE                    Name    Action
38  2013-08-12-36   2013-08-12 14:54:50 John Smith  0
37  2013-08-12-39   2013-08-12 14:54:28 John Smith  3
36  2013-08-12-39   2013-08-12 14:53:24 John Smith  4
35  2013-06-12-91   2013-08-12 14:30:01 John Smith  3
34  2013-06-12-91   2013-08-12 14:29:44 John Smith  4
31  2013-06-12-91   2013-08-12 14:28:39 John Smith  0

我想列出指定日期之间每个唯一TRACKID的ACTION = 0和ACTION = 3之间的时差。

SELECT DISTINCT TIMEDIFF
       (
                (select `date` from hesk_history where `action` = 0),
                (select `date` from hesk_history where `action` = 3 )
       ) AS DIFF

FROM    hesk_history

WHERE `date` BETWEEN '2013-08-12 00:00:00' AND '2013-08-12 23:59:59'

当每个TRACKID存在这些操作时，解决方案应列出每个不同的TRACKID和Action 0与Action 3之间的TIMEDIFF。

TRACKID       DIFF
2013-06-12-91 -00:01:22

Answer 1

尝试像这样加入表格：

SELECT 
    t1.TRACKID,
    t2.date - t1.date
FROM
    table t1
    JOIN table t2 ON t2.TRACKID = t1.TRACKID AND t1.Action = 0 AND t2.Action = 3
WHERE t1.date BETWEEN '2013-08-12 00:00:00' AND '2013-08-12 23:59:59'

Answer 2

下面应该可以工作，我不确定DATEDIFF函数是否在MySQL上，但如果不确定它是否有自己的功能。


SELECT A.TrackID,
       DATEDIFF(A.TrackID,B.TrackID)
FROM hesk_history A
INNER JOIN hesk_history B
ON A.TrackID = B.TrackID AND B.Action=3
WHERE A.TrackID == <your_input> AND A.Action=0

MySQL匹配条件的行之间的时差

2 个答案: