Question

在我之前的问题For Loop Functions in Python中，我无法放置包含命令的函数来为刽子手游戏画一条线。它并没有完全划清界限，我首先怀疑它是for循环或函数的问题。现在我意识到Pygame有一些小故障。

我尝试在加拿大使用此代码解决问题：

b2 = font.render(str(letters[1]), True, (red))
screen.blit(b2, (bPosition))
if hangman1x == -500 and hangman1y == -500:
    hangman1x = (775, 250)
    hangman1y = (775, 50)
    pygame.draw.line(screen, black, (hangman1x), (hangman1y), (5))
    pygame.display.flip()
    time.sleep(0.5)
    bPosition = -500, -500
    b1.x, b1.y = -500, -500
if hangman1x == (775, 250) and hangman1y == (775, 50):
    print 'hi'
    width = 6
    pygame.draw.line(screen, black, (hangman1x), (hangman1y), (5))
    print 'yay'
    pygame.display.flip()

现在这是奇怪的事情。

当你按下B blitting到屏幕上时，它会变成红色，就像它的意思一样，画出完美的线条，然后消失，当B消失时，我理解为什么。在那之后，我添加了额外的代码。（请注意，pygame.draw.line（s）都是相同的），它在shell中打印hi和yay，但它不保留该行。无论如何要解决这个问题？

Answer 1

在调用pygame.draw.line（）之后，您可能会将屏幕重绘为完全白色，这将在线上绘制并隐藏它。我不是像你那样画线，而是从那个

构建一个刽子手类画

class Hangman():
  def __init__(self):
    self.lines = 0 #Number of lines to be drawn

  def draw(self,screen):
    #TODO draw to screen based on self.lines

#More code setting up pygame

drawlist = []
myMan = Hangman()
drawlist.append(myMan)
#mainloop
while 1:
  screen.fill('#000000')
  for item in drawlist:
    item.draw(screen)

这样你每帧重绘你的刽子手，因此他总是被展示

编辑添加了一个正在运行的示例

#!/usr/bin/python
import pygame
pygame.init()

class Hangman():
  def __init__(self):
    self.lines = 0 #Number of lines to be drawn

  def hang(self):
    self.lines += 1

  def draw(self,screen):
    for x in range(self.lines):
      coord1 = (x*10,20)
      coord2 = (x*10,50)
      pygame.draw.line(screen,(0,0,0),coord1,coord2)

size = screenWidth,screenHeight = 200,70
screen = pygame.display.set_mode(size)
pygame.display.flip()

myman = Hangman()

drawlist = []
drawlist.append(myman)
#mainloop
running = True
while running:
  #EVENT HANDLING#
  for event in pygame.event.get():
    if event.type == pygame.QUIT:
      running = False
    if event.type == pygame.KEYDOWN:
      if event.key == 32: #Spacebar
        myman.hang()

  #DRAWING#
  screen.fill((255,255,255))
  for item in drawlist:
    item.draw(screen)
  pygame.display.flip()

Pygame：绘制线条

1 个答案: