Question

我有如下表记录： -

MY_TABLE

        id |      rating | description

         1 |         0.0 | bed
         2 |         1.0 | good
         3 |         0.0 | bed
         4 |         1.0 | good
         5 |         0.0 | bed
         6 |         0.0 | bed
         7 |         0.0 | bed

现在我按评分缩短了这张表，我得到了以下结果。（查询：SELECT * FROM my_table ORDER BY rating DESC）

结果表

        id | rating      | description

         2 |         1.0 | good
         4 |         1.0 | good
         1 |         0.0 | bed
     ==> 3 |         0.0 | bed
         5 |         0.0 | bed
         6 |         0.0 | bed
         7 |         0.0 | bed

现在我想要先前的id = 3记录。

预期结果

        id | rating      | description

         1 |         0.0 | bed

我怎样才能实现它。在单个mysql查询中？请帮帮我。

Answer 1

使用此：

SELECT * FROM my_table ORDER BY rating DESC LIMIT 2,1

Answer 2

试试这个

SELECT prev.id, rating, description
FROM my_table current
JOIN my_table prev
  ON (prev.rating < current.rating) 
     OR (prev.rating = current.rating 
        AND (prev.description < current.description 
            OR (prev.description = current.description AND prev.id < current.id)))
WHERE current.id = @currentId
ORDER BY prev.rating desc, prev.description desc, prev.id desc
LIMIT 1

Answer 3

试试这个以获得快速解决方案：

SELECT * FROM my_table WHERE rating ='0.0'且id＆lt;'3'ORDER BY ID DESC LIMIT 1

这将选择ID低于指定评级为0.0的ID的行。这将在没有排序的情况下工作但是不会检索任何评级为1.0的行，即使它们是下一行。

Answer 4

试试这个：

select * from my_table 
where rating<(select max(rating) from my_table)
and
id<3
limit 1;

获得第二个最后一条记录 - mysql-query

4 个答案: