比较两个变量和和回显缺失的值

Question

我有一个如下变量：

Variable1="PanicA0 PanicA1"
Variable2="PanicA0"

我必须比较variable1和variable2，并且应该将输出回显为PanicA1，即"PanicA1" is not in Varaiable2。我如何使用shell脚本实现这一目标？

Answer 1

• 步骤1：将每个单词的第一个变量拆分为一个数组
• 第2步：迭代数组
• 步骤3：在双括号内使用模式匹配

Variable1="PanicA0 PanicA1"
variable2="PanicA0"

varArr=($Variable1)
for word in "${varArr[@]}"
do
   [[ $variable2 == *${word}* ]] || echo "$word is not in varaiable2"
done

Answer 2

这是脚本

varone=`echo "PanicA0 PanicA1" | cut -d' ' -f1-`
vartwo=`echo "PanicA0" | cut -d' ' -f1-`

for i in $varone; do
    for j in $vartwo; do
        if [[ $i = $j ]]; then 
            echo "Matched: $i"
            break
        else
            echo "$i is not in vartwo"
        fi
    done
done