Question

我想从命令行启动一个应用程序，并立即将XCode 4中的图形调试器附加到它，而无需单击Xcode菜单Product-＆gt; Attach To Progress。是否可以使用bash或Apple脚本编写脚本？

Answer 1

这似乎适用于Xcode-Beta版本6.2（6C121）。对于Xcode，只需更改＆＃34; Xcode-Beta＆＃34;到Xcode。此外，您还想要更改流程名称＆＃34; Staging＆＃34;到你想要附加的过程。

tell application "Xcode-Beta"
activate
end tell

tell application "System Events"
    tell application process "Xcode"
        click (menu item "By Process Identifier (PID) or Name…" of menu 1 of menu item "Attach to Process" of menu 1 of menu bar item "Debug" of menu bar 1)
    end tell
    tell application process "Xcode"
        set value of text field 1 of sheet 1 of window 1 to "Staging"
    end tell
    tell application process "Xcode"
        click button "Attach" of sheet 1 of window 1
    end tell
end tell

Answer 2

适用于 Xcode 12

tell application "Xcode"
    activate
end tell

tell application "System Events"
    tell application process "Xcode"
        click (menu item "Attach to Process by PID or Name…" of menu 1 of menu bar item "Debug" of menu bar 1)
        
    end tell
    tell application process "Xcode"
        set value of text field 1 of sheet 1 of window 1 to "Your App/Process Name"
    end tell
    tell application process "Xcode"
        click button "Attach" of sheet 1 of window 1
    end tell
end tell

tell application "our App/Process Name"
    activate
end tell

XCode 4调试器：从命令行附加到进程

2 个答案: