Question

我使用像twitter和instagram这样的提及系统，你只需要放置@johndoe 我试图做的是能够删除“@”和这些字符之间的名称?，,，]，:，{{1 }}

作为一个例子，我的字符串： (space)

如何获得hey @johnDoe check out this event, be sure to bring @janeDoe:,@johnnyappleSeed?, @johnCitizen] , and @fredNerk，janeDoe，johnnyappleSeed，johnCitizen的数组，而不包含字符fredNerk，?，{{ 1}}，,附在他们身上。

我知道我必须使用]的变体，但我对它没有很强的理解。

Answer 1

这就是你要求的：/\@(.*?)\s/
这就是你真正想要的：/\b\@(.*?)\b/

将其中一个放入preg_match_all()并评估结果数组。

Answer 2

preg_match_all("/\@(.*?)\s/", $string, $result_array);

Answer 3

$check_hash = preg_match_all ("/@[a-zA-Z0-9]*/g", $string_to_match_against, $matches);

然后你可以做类似

的事情

foreach ($matches as $images){
  echo $images."<br />";
}

更新：刚刚意识到您要删除无效字符。更新后的脚本应该这样做。

Answer 4

怎么样：

$str = 'hey @johnDoe check out this event, be sure to bring @janeDoe:,@johnnyappleSeed?, @johnCitizen] , and @fredNerk';
preg_match_all('/@(.*?)(?:[?, \]: ]|$)/', $str, $m);
print_r($m);

<强>输出：

Array
(
    [0] => Array
        (
            [0] => @johnDoe
            [1] => @janeDoe:
            [2] => @johnnyappleSeed?
            [3] => @johnCitizen]
            [4] => @fredNerk
        )

    [1] => Array
        (
            [0] => johnDoe
            [1] => janeDoe
            [2] => johnnyappleSeed
            [3] => johnCitizen
            [4] => fredNerk
        )

)

<强>解释

The regular expression:

(?-imsx:@(.*?)(?:[?, \]: ]|$))

matches as follows:

NODE                     EXPLANATION
----------------------------------------------------------------------
(?-imsx:                 group, but do not capture (case-sensitive)
                         (with ^ and $ matching normally) (with . not
                         matching \n) (matching whitespace and #
                         normally):
----------------------------------------------------------------------
  @                        '@'
----------------------------------------------------------------------
  (                        group and capture to \1:
----------------------------------------------------------------------
    .*?                      any character except \n (0 or more times
                             (matching the least amount possible))
----------------------------------------------------------------------
  )                        end of \1
----------------------------------------------------------------------
  (?:                      group, but do not capture:
----------------------------------------------------------------------
    [?, \]: ]                any character of: '?', ',', ' ', '\]',
                             ':', ' '
----------------------------------------------------------------------
   |                        OR
----------------------------------------------------------------------
    $                        before an optional \n, and the end of
                             the string
----------------------------------------------------------------------
  )                        end of grouping
----------------------------------------------------------------------
)                        end of grouping
----------------------------------------------------------------------

获取php中2个字符之间的子字符串

4 个答案: