Question

我尝试将代码编写为一个简单的文本冒险游戏，从头开始作为编程练习并获得了惊人的结果。这是完整的代码：

//Twisty Passages All Alike.
//An adventure game designed as a practice exercise.
#include <iostream>
#include <string>
using namespace std;

int main()
{
    cout << "\t\tTwisty Passages, All Alike!\n";
    cout << "\tA text adventure by Jellypox Studios.\n";

    //INVENTORY INDEX NUMBERS:
    //0. note
    //1. hammer
    //2. 


    //ROOM NUMBERS:
    //0. living room
    //1. storeroom


    //Setting up the current room.
    int ALL_ITEMS = 10;
    string inventory[ALL_ITEMS];
    int currentRoom = 0;

    string input = "DEFAULT";

    //Room 0: living room.
    bool haveNote = false;
    bool haveHammer = false;

    //Room descriptions
    if (currentRoom == 0)
    {
        cout << "You are in the living room.\nThere are doors to the south and west and a staircase to the north.\nYou can see: a table, a cat, a fireplace.\n\n";
    }
    else if (currentRoom == 1)
    {
        cout << "You are in the storeroom.\nThe room is a jumbled mass of cupboards, hanging sausages, left-out scraps of food and cockroaches.\nThe only thing of interest here is a large chest in the corner.";
    }


    //THE LIVING ROOM
    while (currentRoom == 0)
    {
        cin >> input;
        //THE TABLE
        if (input == "look table" || "look at table")
        {
            cout << "You see: some bones and scraps";
            if (haveHammer = false)
            {
                cout << ", a hammer";
            }
            if (haveNote == false)
            {
                cout << ", a note";
            }
            cout << ".\n\n";
        }
        else if (input == "look scraps" || "look at scraps" || "look bones" || "look at bones")
        {
            cout << "What a mess!\n\n";
        }
        else if (input == "look note" || "look at note" || "read note")
        {
            if (haveNote == false)
            {
                cout << "Pick it up first!\n\n";
            }
            else
            {
                cout << "It reads: \"Gone hunting. Will be back soon.\"";
            }
        }
        else if (input == "get note" || "take note" || "pick up note")
        {
            if (haveNote == false)
            {
                cout << "Got the note.";
                inventory[0] = "note";
                haveNote = true;
            }
            else
            {
                cout << "You already have the note!\n\n";
            }
        }
        else if (input == "look hammer" || "look at hammer")
        {
            cout << "It's just an ordinary hammer.\n\n";
        }
        else if (input == "get hammer" || "take hammer" || "pick up hammer")
        {
            if (haveHammer == false)
            {
                cout << "Got the hammer.\n\n";
                inventory[1] = "hammer";
                haveHammer = true;
            }
            else
            {
                cout << "You already have the hammer!\n\n";
            }
        }
        //ELSWHERE IN THE ROOM
        else if (input == "look cat" || "look at cat")
        {
            cout << "It stares up at you irritably.\n\n";
        }
        else if (input == "look fireplace" || "look at fireplace")
        {
            cout << "A flickering fire warms the house.\n\n";
        }
        else if (input == "south" || "go south")
        {
            //CODE TO MAKE THE DOOR UNLOCKABLE GOES HERE!
            cout << "The door is locked.\n\n";
        }
        else if (input == "west" || "go west")
        {
            currentRoom = 1;
        }
        else if (input == "north" || "go north" || "upstairs" || "go upstairs")
        {
            currentRoom = 2;
        }
        else
        {
            cout << "Say what?";
        }
    }
    return 0;
}

我尝试在输入/输出系统中使用while循环，这样如果你输入“look at table”，它会给你一个表的描述等，但是它会这样做：

look at table
You see: some bones and scraps, a note.

You see: some bones and scraps, a note.

You see: some bones and scraps, a note.

get note
You see: some bones and scraps, a note.

You see: some bones and scraps, a note.

get hammer
You see: some bones and scraps, a note.

You see: some bones and scraps, a note.

go west
You see: some bones and scraps, a note.

You see: some bones and scraps, a note.

我做错了什么？

Answer 1

例如，

此代码中存在拼写错误 if（haveHammer = false）

哪个应该有双倍'='我相信。编译不会对你大喊大叫，但逻辑不是你想要的。

此代码中有非C ++代码，

    if (input == "hall..." || "ass" ）

在C ++中，我们不使用它，尽管它是有效的。它应该是

    if (input =="hall....") || input == "bbbb")

因为我认为你不只是想比较这些字符串文字的内存地址。

（我没有仔细阅读代码，感谢您的评论。

Answer 2

为输入中的每个单词打印一次“你看：有些骨头...”。如果你输入“快速的棕色狐狸跳过懒狗”它可能会打印“你看：......”9次。因此，看起来您的“cin＆gt;＆gt;输入”会将您的输入字符串分解为令牌。您必须弄清楚如何让它读取整行并将其作为一个字符串提供给您;我在C ++上生气，我记不起来了。： - ）

另外，你写道：if（input ==“look table”||“look at table”）

这里的问题是“看表”总是如此，所以表达式总是正确的。你可能想要：if（input ==“look table”|| input ==“look at table”）

C ++ while循环有什么问题？

2 个答案: