最近，我一直在研究我的Noughts and Crosses游戏，但我偶然发现了一个我似乎无法解决的问题。
每当我第一次输入内容时，它都能正常工作并打印出电路板，但是，从那时起，它就会停止检查并打印出电路板。
while(inf){
String temp = input.next();
if(playerTurn == 1){
if(amountP1 <= 3){
if(temp.equalsIgnoreCase("00")){
if(board[0][0] == 0){
board[0][0] = 1;
showBoard(board);
playerTurn = 2;
amountP1++;
}
else{
System.out.println("This space is already occupied!");
}
}
else if(temp.equalsIgnoreCase("01")){
if(board[0][1] == 0){
board[0][1] = 1;
showBoard(board);
playerTurn = 2;
amountP1++;
}
else{
System.out.println("This space is already occupied!");
}
}
else if(temp.equalsIgnoreCase("02")){
if(board[0][2] == 0){
board[0][2] = 1;
showBoard(board);
playerTurn = 2;
amountP1++;
}
else{
System.out.println("This space is already occupied!");
}
}
else if(temp.equalsIgnoreCase("10")){
if(board[1][0] == 0){
board[1][0] = 1;
showBoard(board);
playerTurn = 2;
amountP1++;
}
else{
System.out.println("This space is already occupied!");
}
}
else if(temp.equalsIgnoreCase("11")){
if(board[1][1] == 0){
board[1][1] = 1;
showBoard(board);
playerTurn = 2;
amountP1++;
}
else{
System.out.println("This space is already occupied!");
}
}
else if(temp.equalsIgnoreCase("12")){
if(board[1][2] == 0){
board[1][2] = 1;
showBoard(board);
playerTurn = 2;
amountP1++;
}
else{
System.out.println("This space is already occupied!");
}
}
else if(temp.equalsIgnoreCase("20")){
if(board[2][0] == 0){
board[2][0] = 1;
showBoard(board);
playerTurn = 2;
amountP1++;
}
else{
System.out.println("This space is already occupied!");
}
}
else if(temp.equalsIgnoreCase("21")){
if(board[2][1] == 0){
board[2][1] = 1;
showBoard(board);
playerTurn = 2;
amountP1++;
}
else{
System.out.println("This space is already occupied!");
}
}
else if(temp.equalsIgnoreCase("22")){
if(board[2][2] == 0){
board[2][2] = 1;
showBoard(board);
playerTurn = 2;
amountP1++;
}
else{
System.out.println("This space is already occupied!");
}
}
}
else if(playerTurn == 2){
if(amountP2 <= 3){
if(temp.equalsIgnoreCase("00")){
if(board[0][0] == 0){
board[0][0] = 2;
showBoard(board);
playerTurn = 1;
amountP2++;
}
else{
System.out.println("This space is already occupied!");
}
}
else if(temp.equalsIgnoreCase("01")){
if(board[0][1] == 0){
board[0][1] = 2;
showBoard(board);
playerTurn = 1;
amountP2++;
}
else{
System.out.println("This space is already occupied!");
}
}
else if(temp.equalsIgnoreCase("02")){
if(board[0][2] == 0){
board[0][2] = 2;
showBoard(board);
playerTurn = 1;
amountP2++;
}
else{
System.out.println("This space is already occupied!");
}
}
else if(temp.equalsIgnoreCase("10")){
if(board[1][0] == 0){
board[1][0] = 2;
showBoard(board);
playerTurn = 1;
amountP2++;
}
else{
System.out.println("This space is already occupied!");
}
}
else if(temp.equalsIgnoreCase("11")){
if(board[1][1] == 0){
board[1][1] = 2;
showBoard(board);
playerTurn = 1;
amountP2++;
}
else{
System.out.println("This space is already occupied!");
}
}
else if(temp.equalsIgnoreCase("12")){
if(board[1][2] == 0){
board[1][2] = 2;
showBoard(board);
playerTurn = 1;
amountP2++;
}
else{
System.out.println("This space is already occupied!");
}
}
else if(temp.equalsIgnoreCase("20")){
if(board[2][0] == 0){
board[2][0] = 2;
showBoard(board);
playerTurn = 1;
amountP2++;
}
else{
System.out.println("This space is already occupied!");
}
}
else if(temp.equalsIgnoreCase("21")){
if(board[2][1] == 0){
board[2][1] = 2;
showBoard(board);
playerTurn = 1;
amountP2++;
}
else{
System.out.println("This space is already occupied!");
}
}
else if(temp.equalsIgnoreCase("22")){
if(board[2][2] == 0){
board[2][2] = 2;
showBoard(board);
playerTurn = 1;
amountP2++;
}
else{
System.out.println("This space is already occupied!");
}
}
}
}
}
}
这是印刷电路板的方法：
public static void showBoard(int x[][]){
int rowNumber = 1;
for(int row = 0 ; row < x.length ; row++){
for(int column = 0 ; column < x[row].length ; column++){
if(x[row][column] == 0){
if(rowNumber <= 2){
System.out.print(" E");
rowNumber++;
}
else if(rowNumber == 3){
System.out.println(" E");
rowNumber = 1;
}
}
else if(x[row][column] == 1){
if(rowNumber <= 2){
System.out.print(" X");
rowNumber++;
}
else if(rowNumber == 3){
System.out.println(" X");
rowNumber = 1;
}
}
else if(x[row][column] == 2){
if(rowNumber <= 2){
System.out.print(" O");
rowNumber++;
}
else if(rowNumber == 3){
System.out.println(" O");
rowNumber = 1;
}
}
}
}
}
另外，我知道这个代码是一个很大的混乱，并且有很多其他更有效的方法可以做到这一点，但由于我是一个相当新的程序员，我选择使用功能而不是效率
答案 0 :(得分：4)
您的else if(playerTurn == 2)行需要提取到与if(playerTurn == 1)相同的水平：
if(playerTurn == 1){
if(amountP1 <= 3){
//...
}
else if(playerTurn == 2){
//...
}
}
应该成为
if(playerTurn == 1){
if(amountP1 <= 3){
//...
}
} else if(playerTurn == 2) {
//...
}