Question

我遇到的问题是当我尝试加载 pickled 对象时。我尝试过同时使用pickle.loads和pickle.load以下是结果：

pickle.loads - TypeError: 'str' does not support the buffer interface

pickle.load - TypeError: file must have 'read' and 'readline' attributes

有人可以告诉我在这个过程中我做错了什么吗？谢谢，这是我的代码：

elif str(parser) == 'SwissWithdrawn_Parser':
       # swissprot name changes
       print('Gathering SwissProt update info...')
       cache_hits = 0
       cache_misses = 0
       files = set()

       for f in os.listdir('out/cache/'):
           if os.path.isfile('out/cache/'+f):
               files.add(f)

       for name in sp_lost_names:

           cached = False
           url = 'http://www.uniprot.org/uniprot/?query=mnemonic%3a'+name+ \
               '+active%3ayes&format=tab&columns=entry%20name'
           hashed_url = str(hash(url))

           ################### For Testing Only - use cache ##################
           if hashed_url in files:
               cached = True
               cache_hits += 1
               content = pickle.loads('out/cache/' +hashed_url)  # <-- problematic line
           else:
               cache_misses += 1
               content = urllib.request.urlopen(url)

           # get the contents returned from the HTTPResponse object
           content_list = [x.decode().strip() for x in content.readlines()]
           if not cached:
               with open('out/cache/'+hashed_url, 'wb') as fp:
                   pickle.dump(content_list, fp)
           ####################################################################

           # no replacement
           if len(content_list) is 0:
               change_log['swiss-names'] = 
                  { name : 'withdrawn' }
           # get the new name
           else:
               new_name = content_list[1]
               change_log['swiss-names'] =
                  { name : new_name }

Answer 1

您需要首先读取文件（作为二进制文件bytes）并使用pickle.loads()，或者将打开的文件对象传递给pickle.load()命令。后者是优选的：

with open('out/cache/' +hashed_url, 'rb') as pickle_file:
    content = pickle.load(pickle_file)

这两种方法都不支持从文件名中加载pickle。

Answer 2

如果您正巧将python2移植到3并遇到此错误，则python2和3处理字节不同，导致需要使用'b'选项打开文件句柄。例如在python2 open(file, 'r') as f: my_list = pickle.load(f)中有效，但在python3中无效。相反，您必须使用open(file, 'rb') as f: my_list = pickle.load(f)

打开

无法加载腌制对象

2 个答案: