如何使用hibernate CRITERIA编写此连接查询

Question

select ptm.* from ProofTestMaster ptm LEFT JOIN 
ProofTestApplicationMap ptam on ptm.proofTestID = ptam.proofTestID 
LEFT JOIN ProofTestComapartmentMap ptcm on ptm.proofTestID = ptcm.proofTestID 
where (ptam.applicationID = 3 and ptm.isDeleted = 0) or 
(ptcm.compartmentID = 4 and ptm.isDeleted = 0)

ProofTestApplicationMap和ProofTestComapartmentMap是映射表，并且它们在java端没有实体。

Answer 1

最好为查询添加适当的缩进。优点是：

• 您将理解查询easilly
• 其他人也会很快理解。

所以我为你做了这个。现在查询看起来像：

select 
    ptm.* 
from ProofTestMaster ptm 
    LEFT JOIN ProofTestApplicationMap ptam on ptm.proofTestID = ptam.proofTestID 
    LEFT JOIN ProofTestComapartmentMap ptcm on ptm.proofTestID = ptcm.proofTestID 
where 
    (ptam.applicationID = 3 and ptm.isDeleted = 0) or 
    (ptcm.compartmentID = 4 and ptm.isDeleted = 0);

下面是CriteriaBuilder与Static Metamodel的实现：

CriteriaBuilder criteriaBuilder = entityManager.getCriteriaBuilder();
CriteriaQuery<Long> criteriaQuery = criteriaBuilder.createQuery(Long.class);

Root<ProofTestMaster> mainRoot = criteriaQuery.from(ProofTestMaster.class);

Join<ProofTestMaster, ProofTestApplicationMap> firstJoin = mainRoot.join(ProofTestMaster_.proofTestID, JoinType.LEFT);
Join<ProofTestMaster, ProofTestComapartmentMap> secondJoin = mainRoot.join(ProofTestMaster_.proofTestID, JoinType.LEFT);

Predicate p1 = criteriaBuilder.equal(firstJoin.get(ProofTestApplicationMap_.applicationID),3);
Predicate p2 = criteriaBuilder.equal(mainRoot.get(ProofTestMaster_.isDeleted),0);
Predicate p3 = criteriaBuilder.equal(secondJoin.get(ProofTestComapartmentMap_.compartmentID), 4);
Predicate p4 = criteriaBuilder.and(p1,p2);
Predicate p5 = criteriaBuilder.and(p3,p2);
Predicate p6 = criteriaBuilder.or(p4,p5);

criteriaQuery.where(p6);

criteriaQuery.select(criteriaBuilder.count(mainRoot));

Long count = entityManager.createQuery(criteriaQuery).getSingleResult();

如果你看到上面的代码，总共有6个Predicates，可以放入List。但是为了你的理解我保持这样。

请告诉我它是否对您有所帮助。谢谢，快乐的编码。