Question

基本上，我想知道Excel的COUNTIF的SQL等价物（范围，标准）

我想要这个输出

CALL ID |  Name  | Phone Number | # of Occurrences    
  0001  | Name1  |  0000000000  |        2    
  0002  | Name2  |  1111111111  |        1    
  0003  | Name1  |  0000000000  |        2    
  0004  | Name3  |  2222222222  |        2    
  0005  | Name5  |  4444444444  |        1    
  0006  | Name4  |  3333333333  |        1    
  0007  | Name3  |  2222222222  |        2

不是此输出

CALL ID |  Name  | Phone Number | # of Occurrences    
  0001  | Name1  |  0000000000  |        2    
  0002  | Name2  |  1111111111  |        1    
  0004  | Name3  |  2222222222  |        2    
  0005  | Name5  |  4444444444  |        1    
  0006  | Name4  |  3333333333  |        1

这是一张简化的表格。这是我的复杂表格，这就是结果 Result

我想要的是避免使用2个约会，而是将它们列在单独的行中，以便约会只有1个

这是查询

SELECT
a."Call ID" as "Call ID",
CONCAT(a.Campaign, '-', a."CONTACT ID") as IDENTIFIER,
REPLACE(a."Campaign",'CW-','') as "Campaign",
a."DNIS" as "DNIS",
a."CONTACT ID" as "CONTACT ID",
a."first_name" as "first_name",
a."last_name" as "last_name",
a."city" as "city",
a."street" as "street",
a."zip" as "zip",
a."state" as "state",
a."number2" as "number2",
a."number1" as "number1",
a."Customer ID - real" as "Customer ID - real",
COUNT(a."Call ID") as "Dial Attempts"
FROM  "Five9 Calls" a 
group by 
CONCAT(a.Campaign, '-', a."CONTACT ID"),
REPLACE(a."Campaign",'CW-',''),
a."CONTACT ID",
a."first_name",
a."last_name",
a."city",
a."street",
a."zip",
a."state",
a."number2",
a."number1"

Answer 1

Declan的答案为您提供了与每个电话号码相关联的姓名数量（每个电话号码一行）。

如果您保持相同的行数（即您在问题中描述的布局相同）很重要，则可以使用OVER子句。

SELECT NAME, [PHONE NUMBER], COUNT(NAME) OVER (PARTITION BY [PHONE NUMBER]) AS OCCUR
FROM YOURTABLE

使用OVER，不需要GROUP BY。

Answer 2

如果您需要计算每个电话号码的出现次数（我可以从您的数据中收集），您可以使用以下内容。

SELECT [PHONE NUMBER],COUNT(NAME) AS OCCUR
FROM YOURTABLE
GROUP BY [PHONE NUMBER]

Answer 3

select call_id, name, phone_number, count() over (partition by name, phone_id order by name asc, phone_id asc) occur
From yourtable

每行的出现次数忽略重复项

3 个答案: