Question

我试图根据两个标准返回特定的单元格值。

逻辑：

If ClientID = 1 and BranchID = 1, puts SurveyID

使用Ruby 1.9.3，我想基本查看excel文件以及ClientID和BranchID列中的两个特定值，返回SurveyID中的相应值列。

这是我到目前为止所做的，这是我在网上搜索时发现的。这似乎很有希望，但没有运气：

require 'csv'

# Load file
csv_fname = 'FS_Email_Test.csv'

# Key is the column to check, value is what to match
search_criteria = { 'ClientID' => '1', 
                   'BranchID' => '1' }

options = { :headers      =>  :first_row,
            :converters   =>  [ :numeric ] }

# Save `matches` and a copy of the `headers`
matches = nil
headers = nil

# Iterate through the `csv` file and locate where
# data matches the options.

CSV.open( csv_fname, "r", options ) do |csv|
  matches = csv.find_all do |row|
    match = true
    search_criteria.keys.each do |key|
      match = match && ( row[key] == search_criteria[key] )
    end
    match
  end
  headers = csv.headers
end

# Once matches are found, we print the results
# for a specific row. The row `row[8]` is
# tied specifically to a notes field.

matches.each do |row|
  row = row[1]
  puts row
end

我知道matches.each do |row|之后的最后一段代码是无效的，但是我把它留下来希望对其他人有意义。

如何撰写puts surveyID if ClientID == 1 & BranchID == 1？

Answer 1

你确实很亲密。您唯一的错误是将search_criteria哈希的值设置为字符串'1'而不是数字。由于您converters: :numeric位于find_all，1正在比较'1'与false并获得Hash[row].select { |k,v| search_criteria[k] } == search_criteria。你可以改变它，你已经完成了。

或者这应该适合你。

关键是行

Hash[row]

search_criteria将行转换为哈希而不是数组数组。 Select生成一个新哈希，该哈希只包含require 'csv' # Load file csv_fname = 'FS_Email_Test.csv' # Key is the column to check, value is what to match search_criteria = { 'ClientID' => 1, 'BranchID' => 1, } options = { headers: :first_row, converters: :numeric, } # Save `matches` and a copy of the `headers` matches = nil headers = nil # Iterate through the `csv` file and locate where # data matches the options. CSV.open(csv_fname, 'r', options) do |csv| matches = csv.find_all do |row| Hash[row].select { |k,v| search_criteria[k] } == search_criteria end headers = csv.headers end p headers # Once matches are found, we print the results # for a specific row. The row `row[8]` is # tied specifically to a notes field. matches.each { |row| puts row['surveyID'] }中显示的那些元素。然后只需比较两个哈希值，看它们是否相同。

{{1}}

Answer 2

...可能

require 'csv'

b_headers = false
client_id_col = 0
branch_id_col = 0
survey_id_col = 0

CSV.open('FS_Email_Test.csv') do |file|
  file.find_all do |row|
    if b_headers == false then

      client_id_col = row.index("ClientID")
      branch_id_col = row.index("BranchID")
      survey_id_col = row.index("SurveyID")
      b_headers = true

      if branch_id_col.nil? || client_id_col.nil? || survey_id_col.nil? then
        puts "Invalid csv file - Missing one of these columns (or no headers):\nClientID\nBranchID\nSurveyID"
        break
      end

    else
      puts row[survey_id_col] if row[branch_id_col] == "1" && row[client_id_col] == "1"
    end

  end
end

使用Ruby解析CSV数据

2 个答案: