Question

想象一下下面的MySQL订单表：

id | name
1  | Mike
2  | Steve
3  | Janet
4  | Juliet
5  | Mike
6  | Jane

这是我目前的查询：

SELECT * FROM table ORDER BY id DESC

但是，我想通过name对这些内容进行“分组”，这样我就可以从同一个人那里获得相同的订单，但是，我无法进行ORDER BY name。

这是我想要的输出：

id | name
6  | Jane
5  | Mike
1  | Mike
4  | Juliet
3  | Janet
2  | Steve

这个输出的查询是什么？

Answer 1

E.g：

SELECT y.id
     , y.name  
  FROM my_table x 
  JOIN my_table y 
    ON y.name = x.name 
 GROUP 
    BY name
     , id 
 ORDER 
    BY MAX(x.id) DESC
     , id DESC;

Answer 2

您需要进行特殊计算才能获得行位置。

SELECT  a.*
FROM    tableName a
        INNER JOIN
        (
            SELECT  Name, 
                    @ord := @ord + 1 ord
            FROM        
                    (
                        SELECT  MAX(ID) ID, NAME
                        FROM    TableName 
                        GROUP   BY Name
                    ) a, (SELECT @ord := 0) b
            ORDER   BY ID DESC
        ) b ON a.Name = b.Name
ORDER   BY b.ord, a.ID DESC

SQLFiddle Demo

Answer 3

您可以通过双ORDER BY：

来完成

SELECT * FROM t ORDER BY name ASC, id DESC

Answer 4

SELECT * FROM table1 
ORDER BY field(NAME,'Mike','Jane') desc,
`ID` desc;

<强> exactly as you asked

Answer 5

如果您想拥有更通用的SQL，也可以尝试此查询。

SELECT id, name 
FROM ( SELECT id, name, (SELECT MAX(id) from Table1 where name=t.name) AS max_id 
     FROM Table1 AS t 
     ORDER BY max_id DESC, id DESC) as x

Answer 6

如何使用group by？您可以按名称对其进行分组，然后订购......

按两列排序

6 个答案: