我收到了最新的推文，结果如下：
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"created_at": "Wed Aug 28 11:50:22 +0000 2013",
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"text": "\"I fear we'll get ourselves involved in another endless conflict\" - Ukip's @Nigel_Farage on UK's #Syria decision http:\/\/t.co\/3iMlO9BHks",
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"created_at": "Wed Aug 28 11:27:11 +0000 2013",
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"text": "International agreement, legal basis, support in country - @HarrietHarman on criteria needed to support Syria action http:\/\/t.co\/I5fWeyt9gl",
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我如何使用它，以便我可以从阵列中挑选推文，例如。 $tweets[2];我尝试了json_decode，但没有运气。
答案 0 :(得分：1)
您可以尝试将第二个参数传递给json_decode，它会将所有json数据转储为关联数组 link
答案 1 :(得分：0)
如果您尝试将JSON输出存储在字符串中，则由于其中未转义的单引号，它将失败。
例如，JSON输出中包含以下文本：
"text": "\"I fear we'll get ourselves involved in another endless conflict\"
//------^
因此，如果您尝试将JSON分配给字符串，它将失败并产生解析错误，因为它中包含单引号。因为您的JSON包含双引号，所以您也不能使用它。
要告诉PHP忽略引号并将其解释为字符串，您可以使用heredoc语法，如下所示：
$string = <<<JSON
... json ...
JSON;
$json = json_decode($string);
echo $json[0]->text."\n";
echo $json[1]->text."\n";
注意：如果您想要获得关联数组，可以将json_decode()的第二个参数传递为TRUE。