Question

我有一个名为Box和PackageBox的蹩脚测试类。 Box使用Builder Pattern和PackageBox，它应该扩展Box

这是一些代码

package console.app.model;

public class Box {

private String name = "";
private int weight = 0;
private int width = 0;
private int height = 0;

// Box instance for comparison on method equals().
private static Box comparisonBox;

public static class Builder {

    private String name = "";
    private int weight = 0;
    private int width = 0;
    private int height = 0;

    public Builder(String name) {
        this.name = name;
    }

    public Builder weight(int weight) {
        this.weight = weight;
        return this;
    }

    public Builder width(int width) {
        this.width = width;
        return this;
    }

    public Builder height(int height) {
        this.height = height;
        return this;
    }

    public Box build() {
        return new Box(this);
    }

}

private Box(Builder builder) {
    name = builder.name;
    weight = builder.weight;
    width = builder.width;
    height = builder.height;
}

    // Setters and getters, etc.

}

如何将Box扩展到PackageBox？谢谢，如果出现问题，请在Box类中告诉我或要替换的内容。

Answer 1

向Box添加一个受保护的构造函数，然后将其子类化，从PackageBox构造函数中调用受保护的构造函数。但是，如果要使用该路径，则需要为PackageBox实现新的Builder。

可以扩展使用Builder模式和私有构造函数的类吗？

1 个答案: