如何让ttk.Treeview行可编辑?

时间:2013-09-01 19:32:40

标签: python treeview tkinter ttk

  

有没有办法使用ttk Treeview和可编辑的行?

我的意思是它应该更像是一张桌子。例如,双击项目使#0列'可编辑'。

如果无法做到这一点,任何允许鼠标选择项目的方法都可以。我在tkdocs或其他文件中没有发现任何提及。

5 个答案:

答案 0 :(得分:4)

经过长时间的研究,我没有找到这样的功能,所以我猜有没有。 Tk是一个非常简单的界面,它允许程序员从基础构建“高级”功能。所以我希望这样做。

def onDoubleClick(self, event):
    ''' Executed, when a row is double-clicked. Opens 
    read-only EntryPopup above the item's column, so it is possible
    to select text '''

    # close previous popups
    self.destroyPopups()

    # what row and column was clicked on
    rowid = self._tree.identify_row(event.y)
    column = self._tree.identify_column(event.x)

    # clicked row parent id
    parent = self._tree.parent(rowid)

    # do nothing if item is top-level        
    if parent == '':
        return

    # get column position info
    x,y,width,height = self._tree.bbox(rowid, column)

    # y-axis offset
    pady = height // 2

    # place Entry popup properly         
    url = self._tree.item(rowid, 'text')
    self.entryPopup = EntryPopup(self._tree, url)
    self.entryPopup.place( x=0, y=y+pady, anchor=W, relwidth=1)

这是一个将ttk.Treeview组成self._tree

的类中的方法

然后EntryPopup是一个非常简单的Entry子类:

class EntryPopup(Entry):

    def __init__(self, parent, text, **kw):
        ''' If relwidth is set, then width is ignored '''
        super().__init__(parent, **kw)

        self.insert(0, text) 
        self['state'] = 'readonly'
        self['readonlybackground'] = 'white'
        self['selectbackground'] = '#1BA1E2'
        self['exportselection'] = False

        self.focus_force()
        self.bind("<Control-a>", self.selectAll)
        self.bind("<Escape>", lambda *ignore: self.destroy())

    def selectAll(self, *ignore):
        ''' Set selection on the whole text '''
        self.selection_range(0, 'end')

        # returns 'break' to interrupt default key-bindings
        return 'break'

答案 1 :(得分:2)

您还可以弹出一个工具窗口,其中包含使用条目列出的可编辑字段来更新值。此示例具有包含三列的树视图,并且不使用子类。

双击双击:

def OnDoubleClick(self, treeView):
    # First check if a blank space was selected
    entryIndex = treeView.focus()
    if '' == entryIndex: return

    # Set up window
    win = Toplevel()
    win.title("Edit Entry")
    win.attributes("-toolwindow", True)

    ####
    # Set up the window's other attributes and geometry
    ####

    # Grab the entry's values
    for child in treeView.get_children():
        if child == entryIndex:
            values = treeView.item(child)["values"]
            break

    col1Lbl = Label(win, text = "Value 1: ")
    col1Ent = Entry(win)
    col1Ent.insert(0, values[0]) # Default is column 1's current value
    col1Lbl.grid(row = 0, column = 0)
    col1Ent.grid(row = 0, column = 1)

    col2Lbl = Label(win, text = "Value 2: ")
    col2Ent = Entry(win)
    col2Ent.insert(0, values[1]) # Default is column 2's current value
    col2Lbl.grid(row = 0, column = 2)
    col2Ent.grid(row = 0, column = 3)

    col3Lbl = Label(win, text = "Value 3: ")
    col3Ent = Entry(win)
    col3Ent.insert(0, values[2]) # Default is column 3's current value
    col3Lbl.grid(row = 0, column = 4)
    col3Ent.grid(row = 0, column = 5)

    def UpdateThenDestroy():
        if ConfirmEntry(treeView, col1Ent.get(), col2Ent.get(), col3Ent.get()):
            win.destroy()

    okButt = Button(win, text = "Ok")
    okButt.bind("<Button-1>", lambda e: UpdateThenDestroy())
    okButt.grid(row = 1, column = 4)

    canButt = Button(win, text = "Cancel")
    canButt.bind("<Button-1>", lambda c: win.destroy())
    canButt.grid(row = 1, column = 5)

然后确认更改:

def ConfirmEntry(self, treeView, entry1, entry2, entry3):
    ####
    # Whatever validation you need
    ####

    # Grab the current index in the tree
    currInd = treeView.index(treeView.focus())

    # Remove it from the tree
    DeleteCurrentEntry(treeView)

    # Put it back in with the upated values
    treeView.insert('', currInd, values = (entry1, entry2, entry3))

    return True

以下是删除条目的方法:

def DeleteCurrentEntry(self, treeView):
    curr = treeView.focus()

    if '' == curr: return

    treeView.delete(curr)

答案 2 :(得分:0)

我不知道如何使行可编辑,但要捕获单击某行,您可以使用<<TreeviewSelect>>虚拟事件。这将使用bind()方法绑定到例程,然后使用selection()方法获取所选项目的ID。

这些是来自现有程序的片段,但显示了基本的调用序列:

# in Treeview setup routine
    self.tview.tree.bind("<<TreeviewSelect>>", self.TableItemClick)

# in TableItemClick()
    selitems = self.tview.tree.selection()
    if selitems:
        selitem = selitems[0]
        text = self.tview.tree.item(selitem, "text") # get value in col #0

答案 3 :(得分:0)

这仅用于为构造函数中设置的指定路径创建树。您可以将事件绑定到该树上的项目。保留事件功能的方式是可以以多种方式使用该项目。在这种情况下,双击时会显示项目的名称。希望这有助于某人。

    import ttk
    from Tkinter import*
    import os*

    class Tree(Frame):

    def __init__(self, parent):
        Frame.__init__(self, parent)
        self.parent = parent
        path = "/home/...."
        self.initUI(path)

    def initUI(self, path):
        self.parent.title("Tree")
        self.tree = ttk.Treeview(self.parent)
        self.tree.bind("<Double-1>", self.itemEvent)
        yScr = ttk.Scrollbar(self.tree, orient = "vertical", command = self.tree.yview)
        xScr = ttk.Scrollbar(self.tree, orient = "horizontal", command = self.tree.xview)
        self.tree.configure(yscroll = yScr.set, xScroll = xScr.set)
        self.tree.heading("#0", text = "My Tree", anchor = 'w')
        yScr.pack(side = RIGHT, fill = Y)

        pathy = os.path.abspath(path) 
        rootNode = self.tree.insert('', 'end', text = pathy, open = True)
        self.createTree(rootNode, pathy)

        self.tree.pack(side = LEFT, fill = BOTH, expand = 1, padx = 2, pady = 2)

        self.pack(fill= BOTH, expand = 1) 

    def createTree(self, parent, path)
        for p in os.listdir(path)
            pathy = os.path.join(path, p)
            isdir = os.path.isdir(pathy)
            oid = self.tree.insert(parent, 'end' text = p, open = False)
            if isdir:
               self.createTree(oid, pathy)

    def itemEvent(self, event):
        item = self.tree.selection()[0] # now you got the item on that tree
        print "you clicked on", self.tree.item(item,"text")



    def main():
        root = Tk.Tk()
        app = Tree(root)
        root.mainloop()

    if __name__ == '__main__'
       main()

答案 4 :(得分:0)

from tkinter import ttk
from tkinter import *

root = Tk()
columns = ("Items", "Values")
Treeview = ttk.Treeview(root, height=18, show="headings", columns=columns)  # 

Treeview.column("Items", width=200, anchor='center')
Treeview.column("Values", width=200, anchor='center')

Treeview.heading("Items", text="Items")
Treeview.heading("Values", text="Values")

Treeview.pack(side=LEFT, fill=BOTH)

name = ['Item1', 'Item2', 'Item3']
ipcode = ['10', '25', '163']
for i in range(min(len(name), len(ipcode))):
    Treeview.insert('', i, values=(name[i], ipcode[i]))


def treeview_sort_column(tv, col, reverse):
    l = [(tv.set(k, col), k) for k in tv.get_children('')]
    l.sort(reverse=reverse)
    for index, (val, k) in enumerate(l):
        tv.move(k, '', index)
        tv.heading(col, command=lambda: treeview_sort_column(tv, col, not reverse))


def set_cell_value(event):
    for item in Treeview.selection():
        item_text = Treeview.item(item, "values")
        column = Treeview.identify_column(event.x)
        row = Treeview.identify_row(event.y)
    cn = int(str(column).replace('#', ''))
    rn = int(str(row).replace('I', ''))
    entryedit = Text(root, width=10 + (cn - 1) * 16, height=1)
    entryedit.place(x=16 + (cn - 1) * 130, y=6 + rn * 20)

    def saveedit():
        Treeview.set(item, column=column, value=entryedit.get(0.0, "end"))
        entryedit.destroy()
        okb.destroy()

    okb = ttk.Button(root, text='OK', width=4, command=saveedit)
    okb.place(x=90 + (cn - 1) * 242, y=2 + rn * 20)


def newrow():
    name.append('to be named')
    ipcode.append('value')
    Treeview.insert('', len(name) - 1, values=(name[len(name) - 1], ipcode[len(name) - 1]))
    Treeview.update()
    newb.place(x=120, y=(len(name) - 1) * 20 + 45)
    newb.update()


Treeview.bind('<Double-1>', set_cell_value)
newb = ttk.Button(root, text='new item', width=20, command=newrow)
newb.place(x=120, y=(len(name) - 1) * 20 + 45)

for col in columns:
    Treeview.heading(col, text=col, command=lambda _col=col: treeview_sort_column(Treeview, _col, False))


root.mainloop()

经过大量的研究,我的项目得到了这段代码,对我有很大帮助。 双击要编辑的元素,进行所需的更改,然后单击“确定”按钮 我认为这正是您想要的

#python #tkinter #treeview #editablerow

New row Editable row

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