EF 5.0(数据库优先模型)不在一个表上工作

时间:2013-09-07 14:00:36

标签: entity-framework-5

我有一个名为TBLFIRM的数据库表。我正在使用acc数据库优先模型。 EF准备sql错误。这个对象有什么问题?

谢谢

我的语法,一个非常简单的电话:

TBLFIRM d = VT.TBLFIRMs.FirstOrDefault(p => p.ID > 0);

EF 5准备的SQL语法

SELECT TOP (1) 
[Extent1].[ID] AS [ID], 
[Extent1].[DISTID] AS [DISTID], 
[Extent1].[SESSIONKEY] AS [SESSIONKEY], 
[Extent1].[NAME] AS [NAME], 
[Extent1].[PHONE] AS [PHONE], 
[Extent1].[EMAIL] AS [EMAIL], 
[Extent1].[CREATEUSER] AS [CREATEUSER], 
[Extent1].[CREATEDATE] AS [CREATEDATE], 
[Extent1].[UPDATEUSER] AS [UPDATEUSER], 
[Extent1].[UPDATEDATE] AS [UPDATEDATE], 
[Extent1].[AUTHORIZEDUSERNAME] AS [AUTHORIZEDUSERNAME], 
[Extent1].[AUTHORIZEDUSEREMAIL] AS [AUTHORIZEDUSEREMAIL], 
[Extent1].[AUTHORIZEDUSERPHONE] AS [AUTHORIZEDUSERPHONE], 
[Extent1].[SENDEMAIL] AS [SENDEMAIL], 
[Extent1].[REPLYEMAIL] AS [REPLYEMAIL], 
[Extent1].[ACTIVE] AS [ACTIVE], 
[Extent1].[CANLOGIN] AS [CANLOGIN], 
[Extent1].[INTERNALNAME] AS [INTERNALNAME], 
[Extent1].[TBLDISTRIBUTOR_ID] AS [TBLDISTRIBUTOR_ID]
FROM [dbo].[TBLFIRMs] AS [Extent1]
WHERE [Extent1].[ID] > 0

上下文类

public DbSet<TBLFIRM> TBLFIRMs { get; set; }

TBLFirm类

 public partial class TBLFIRM
    {
        public TBLFIRM()
        {
            this.TBLFIRMSETTINGS = new HashSet<TBLFIRMSETTING>();
            this.TBLFIRMSMTPs = new HashSet<TBLFIRMSMTP>();
            this.TBLMAILFIRMMATCHes = new HashSet<TBLMAILFIRMMATCH>();
            this.TBLMAILGROUPs = new HashSet<TBLMAILGROUP>();
            this.TBLMAILTEMPLATEs = new HashSet<TBLMAILTEMPLATE>();
            this.TBLSCHEDULEs = new HashSet<TBLSCHEDULE>();
            this.TBLUSERGROUPs = new HashSet<TBLUSERGROUP>();
            this.TBLUSERS = new HashSet<TBLUSER>();
        }

        public int ID { get; set; }
        public int DISTID { get; set; }
        public string SESSIONKEY { get; set; }
        public string NAME { get; set; }
        public string PHONE { get; set; }
        public string EMAIL { get; set; }
        public string CREATEUSER { get; set; }
        public Nullable<System.DateTime> CREATEDATE { get; set; }
        public string UPDATEUSER { get; set; }
        public Nullable<System.DateTime> UPDATEDATE { get; set; }
        public string AUTHORIZEDUSERNAME { get; set; }
        public string AUTHORIZEDUSEREMAIL { get; set; }
        public string AUTHORIZEDUSERPHONE { get; set; }
        public string SENDEMAIL { get; set; }
        public string REPLYEMAIL { get; set; }
        public Nullable<bool> ACTIVE { get; set; }
        public Nullable<bool> CANLOGIN { get; set; }
        public string INTERNALNAME { get; set; }

        public virtual TBLDISTRIBUTOR TBLDISTRIBUTOR { get; set; }
        public virtual ICollection<TBLFIRMSETTING> TBLFIRMSETTINGS { get; set; }
        public virtual ICollection<TBLFIRMSMTP> TBLFIRMSMTPs { get; set; }
        public virtual ICollection<TBLMAILFIRMMATCH> TBLMAILFIRMMATCHes { get; set; }
        public virtual ICollection<TBLMAILGROUP> TBLMAILGROUPs { get; set; }
        public virtual ICollection<TBLMAILTEMPLATE> TBLMAILTEMPLATEs { get; set; }
        public virtual ICollection<TBLSCHEDULE> TBLSCHEDULEs { get; set; }
        public virtual ICollection<TBLUSERGROUP> TBLUSERGROUPs { get; set; }
        public virtual ICollection<TBLUSER> TBLUSERS { get; set; }
    }

1 个答案:

答案 0 :(得分:0)

经过深入研究后,由于BRian Rogers @ Code First vs. Database First的答复,我能够找到并解决问题。

如果您正在接近数据库或模型优先,则连接字符串必须具有元数据,否则EF会将其解释为代码优先方法。

当我从一个网站调用保存EF对象的库时,web.config的connectionstring是一个plaing数据库连接。

<add name="EmmContext" connectionString="Data Source=.;Initial Catalog=GPMM;Persist Security Info=True;User ID=********;Pwd=******" providerName="System.Data.SqlClient"/>

将其更改为

<add name="EmmContext" connectionString="metadata=res://*/DAL.DBModel.csdl|res://*/DAL.DBModel.ssdl|res://*/DAL.DBModel.msl;provider=System.Data.SqlClient;provider connection string=&quot;data source=.;initial catalog=GPMM;persist security info=True;user id=*******;password=********;MultipleActiveResultSets=True;App=EntityFramework&quot;" providerName="System.Data.EntityClient"/>

它就像一个魅力。

只想分享这种特殊体验。谢谢Brian Rogers! : - )