我该如何修复以下VBA代码

时间:2013-09-17 20:27:05

标签: ms-access ms-access-2007 access-vba ms-access-2010 ms-access-2003

此代码用于填充表单中的文本框,其中sql查询代表hr_id从表RR_info获取数据。它将rr_info的hr_id与listbox的有界值进行比较。

 Private Sub Form_Load()
 Dim SQL As String
 Dim db As Database
 Dim rs As DAO.Recordset

 SQL = "select * from RR_info where hr_id = " & Forms![hhrrr]![List38] & ";"
 Set db = CurrentDb
 Set rs = db.OpenRecordset(SQL)
                                'DoCmd.RunSQL SQL 'at this point it gives me error 2342
 Me.RR_ID.value = rs!RR_ID
 Me.HR_ID.value = rs!HR_ID 
 Me.Room_No.value = rs![Room No] 
 Me.No_of_Beds.value = rs!No_of_Beds
 Me.Room_Category.value = rs!Room_Category

 Set rs = Nothing
 Set db = Nothing
 End Sub

1 个答案:

答案 0 :(得分:2)

你不需要字符串“DoCmd.RunSQL SQL”。 并且最好使用.Value insted of .Text