Question

我尝试通过POST请求将通知链接和deviceID发送到Web上的脚本。问题是脚本只接收空参数。我跟着另一个例子，我的代码看起来像这样：

WebClient wc = new WebClient();
            System.Diagnostics.Debug.WriteLine("sending rquest");
            var URI = new Uri("http://www.jack-prove.comuv.com/update_link.php");
            wc.UploadStringCompleted += new UploadStringCompletedEventHandler(wc_UploadStringCompleted);
            byte[] myDeviceID = (byte[])Microsoft.Phone.Info.DeviceExtendedProperties.GetValue("DeviceUniqueId");
            string ID = Convert.ToBase64String(myDeviceID);
            String par = "?link=" + e.ChannelUri.ToString() + "&ID=" + ID;
            MessageBox.Show(par);
            wc.UploadStringAsync(URI, "POST", par);

注意：ID字符串包含'='字符这可能是问题吗？我试图从网上调用脚本，它甚至可以使用'='

任何想法？

Answer 1

解决了，感谢this question

使用Http client Library

using System.Net.Http;
var values = new List<KeyValuePair<string, string>>
{
      new KeyValuePair<string, string>("link", e.ChannelUri.ToString()),
      new KeyValuePair<string, string>("ID", ID)
};
var httpClient = new HttpClient(new HttpClientHandler());
HttpResponseMessage response = await httpClient.PostAsync(URI, new FormUrlEncodedContent(values));
response.EnsureSuccessStatusCode();
var responseString = await response.Content.ReadAsStringAsync();

WIndows Phone：POST请求不起作用

1 个答案: