Question

我正在尝试编写一个程序，该程序将生成1到100之间的随机数，然后询问用户猜测。此时，如果猜测是正确的，它会告诉他们，反之亦然，如果这是错误的。

到目前为止我所拥有的是：

import random

def playGame2():
    number = random.randint(1,100)
    guess = input("I'm thinking of a number between 1 and 100. Guess what it is: ")
    if str(number) == guess:
        print("That is correct!")
    else:
        print("Nope, I was thinking of" +str(number))

当我运行该程序时，它只给我<function playGame2 at 0x0000000002D3D2F0>。为什么这样做？

Answer 1

您必须执行该功能，您的输出意味着您执行了类似

的操作

print(playGame2)

而不是

playGame2()

Answer 2

def playGame2():
    number = random.randrange(1,100)
    guess = input("I'm thinking of a number between 1 and 100. Guess what it is: ")
    if str(number) == guess:
        print("That is correct!")
    else:
        print("Nope, I was thinking of %s" % number)

试试吧。我刚刚运行它工作正常。要在空闲时使用输入playGame2（）或可以访问它的地方。

Answer 3

你需要告诉python它有一个主要功能尝试在代码末尾包含此内容：

if __name__ == "__main__":
    playGame2()

并将其放在开头：

# -*- coding: UTF-8 -*-

位于代码顶部，用于指定您使用的Python文件的编码方式。见http://www.python.org/dev/peps/pep-0263/

希望它会对你有所帮助。

Answer 4

import random


guess=99 

count=0  

no = random.randint(1,100)  


print("Welcome to the guessing game!")



while guess != no :  
    guess = int(input("Guess a number: ")) 

    if guess < no : 
        print("Higher") 
        count+=1  

    if guess > no :
        print("Lower") 
        count+=1  

    if (guess==no):
        print("You win, the number was indeed:",no)
        print("It took you a total of:",count,"tries")

Python随机数游戏

4 个答案: