Question

如何将其反序列化为变量？ C ＃。举个例子，已经是第二天，没有进入库JSON.NET

{"messages":[{"text":"TEXT MESSAGE","channel":"main":"from":"USERNAME","fromid":651765,"t":1379970985409,"tc":"f16d7e"}}}

所以

void timer_Tick(object sender, EventArgs e)
        {


            string json = @"{""messages"":[{""text"":""TEXT MESSAGE"",""channel"":""main"":""from"":""USERNAME"",""fromid"":651765,""t"":1379970985409,""tc"":""f16d7e""}}} ";


            dynamic stuff = Newtonsoft.Json.JsonConvert.DeserializeObject(json);
            string color = stuff.text;
            label1.Text = color;


        }

解析值后，遇到意外字符::。路径＆＃39;消息[0] .channel＆＃39;，第1行，第52位。

Answer 1

我认为main和from之间的冒号必须是逗号。第二个结束卷曲应该是平方卷曲。

所以你的字符串：

@"{""messages"":[{""text"":""TEXT MESSAGE"",""channel"":""main"":""from"":""USERNAME"",""fromid"":651765,""t"":1379970985409,""tc"":""f16d7e""}}} ";

应该是这样的：

@"{""messages"":[{""text"":""TEXT MESSAGE"",""channel"":""main"",""from"":""USERNAME"",""fromid"":651765,""t"":1379970985409,""tc"":""f16d7e""}]} ";

C＃如何将其反序列化为变量？

1 个答案: