Question

Parse error: syntax error, unexpected '.', expecting

我收到此错误

Parse error: syntax error, unexpected '.', expecting '}' in /home/l2hantol/public_html/acp/core.php on line 37

第37行

function testServer($hostname,$user,$password,$database) {
    try {
        $handler = new PDO("mysql:host={$myip.zapto.org};dbname={$gameserver}",$root,$mypassword);
        $handler = null;
        return true;
    } catch (PDOException $e) {
        return false;
    }
}

// Classes

class template {
    public $template;

    function load($filepath) {
        $this->template = preg_replace("#\{(.*)\}#","<?php echo $1; ?>",file_get_contents($filepath));

Answer 1

什么是$myip.zapto.org？可能你想要这样的东西：

"mysql:host={$myip};dbname={$gameserver}"

或者如果你需要构建一个更复杂的字符串，可以在外面用以下内容完成：

$host = $myip . "zapto.org"
$handler = new PDO("mysql:host={$host};dbname={$gameserver}",$root,$mypassword);

修改

如果myip.zapto.org只是您的域名，则不需要$或{}，因此您只需撰写：

$handler = new PDO("mysql:host=myip.zapto.org;dbname={$gameserver}",$root,$mypassword);

Answer 2

这应该解决它：

function testServer($hostname,$user,$password,$database) {
    try {
    $handler = new PDO("mysql:host={$myip}.zapto.org;dbname={$gameserver}",$root,$mypassword);
    $handler = null;
    return true;
} catch (PDOException $e) {
    return false;
}
}

// Classes

class template {
public $template;

function load($filepath) {
    $this->template = preg_replace("#\{(.*)\}#","<?php echo $1; ?>",
file_get_contents($filepath));

Answer 3

$handler = new PDO("mysql:host={$myip.zapto.org};dbname={$gameserver}"...
                                     -^       ^-

您的连接查询中的此部分不视为字符串。

你可能想要：

$handler = new PDO("mysql:host={$myip}.zapto.org;dbname={$gameserver}" ...

尽管sprintf()看起来更清晰：

$handler = new PDO(sprintf('mysql:host=%s.zapto.org;dbname=%s', $host, $dbname), 
$myip, $gameserver);

解析错误：语法错误，意外'。'，期待

3 个答案: