如何将信息传递到自定义ArrayAdapter的getView?

时间:2013-09-26 19:42:08

标签: android android-adapter

我的申请表中有以下课程:

public class Player implements Parcelable {
    private String name;
    private int playerColor;
    private int[] scores;
    ...
}

如何告诉我的ArrayAdapter的getView方法在相关的列表视图中显示得分数组的哪个元素?我想根据活动中的信息在ListView中显示player.name字段,以及player.scores数组的特定元素。

public class PlayerGameAdapter extends ArrayAdapter<Player> {
private ArrayList<Player> entries;
private Activity activity;

 public PlayerGameAdapter(Activity a, int viewResourceId, ArrayList<Player> entries) {
    super(a, viewResourceId, entries);
    this.entries = entries;
    this.activity = a;
}

public static class ViewHolder {
    public Button buttonName;
}

@Override
public View getView(int position, View convertView, ViewGroup parent) {
    View v = convertView;
    ViewHolder holder;
    if (v == null) {
        LayoutInflater vi =
                (LayoutInflater) activity.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
        v = vi.inflate(R.layout.listview_row_player_game, null);
        holder = new ViewHolder();
        holder.buttonName = (Button) v.findViewById(R.id.buttonGamePlayerListName);
        v.setTag(holder);
    } else
        holder = (ViewHolder) v.getTag();

    final MiniGolfPlayer player = entries.get(position);
    if (player != null) {
        holder.buttonName.setText(player.getName() + " - " + player.scores[ELEMENT]);
    }
    return v;
}

}

1 个答案:

答案 0 :(得分:1)

将位置变量添加到您的玩家类。

public class Player implements Parcelable {
    private String name;
    private int playerColor;
    private int[] scores;
    private int position; // also add the get and set methods
}

在您的活动中,您可以单独更改要为每位玩家显示的分数位置。

((Player)entries.get(0)).setPosition(AnyValueYouWant);
((Player)entries.get(1)).setPosition(AnotherValue);

然后通知你的适配器刷新listview:

PlayerGameAdapter.notifyDataSetChanged();

这对你有用吗?或者你期待别的东西。