Question

我试图计算每天每小时的平均帖子，我必须这样做113个月。 Post表中有此属性timePosted，DatePosted和Text。我还需要加入两个表格帖子和帖子，因为我只想获得类别ID 3。

到目前为止，这是我已经完成的查询。

select datePost as daytime,
  HOUR(timePost) as thehour, 
  count(TEXT) as thecount
  from post, thread
  where date(post.datePost) BETWEEN '2010-05-01' AND '2010-05-31'
  and post.threadID = thread.threadID 
  and thread.CatID = 3
  group by datePost, thehour

上面的子查询将此返回给我：

daytime       thehour    thecount
'2010-05-01', '0',       '3'
'2010-05-01', '1',       '16'
'2010-05-01', '2',       '2'
'2010-05-01', '4',       '1'
'2010-05-01', '7',       '1'

我尝试做平均但是问题是它返回了与数字相同的数字。示例thecount为3，然后Avg返回3.00000

所以我试图得到这个结果：

daytime       thehour    thecount      Avg
'2010-05-01', '0',       '3'           #
'2010-05-01', '1',       '16'          #
'2010-05-01', '2',       '2'           #
'2010-05-01', '4',       '1'           #
'2010-05-01', '7',       '1'           #

Answer 1

按照

分割所需的任何内容进行分组

select month(timePost), day(timePost), hour(timePost),avg(the_count)
from
(
  select datePost as the_day,
  timePost, 
  count(TEXT) as the_count
  from post, thread
  where post.datePost = '2010-05-03'
  and post.threadID = thread.threadID 
  and thread.CatID = 3
  group by the_day,the_hour
) s
group by 1,2,3

以文字的形式获取星期几，请使用

case dayofweek(date) when 1 then 'sunday' when 2 then 'monday' .... end as dayofweek

额外的百分比

select datePost as daytime,
  HOUR(timePost) as thehour, 
  count(TEXT) as thecount,
  count(TEXT)/thecount_daily as percent_this_hour
  from post 
  inner join  thread on  post.threadID = thread.threadID 
  inner join (  select datePost as daytime_daily,
                count(TEXT) as thecount_daily
              from post inner join thread on post.threadID = thread.threadID
              where date(post.datePost) BETWEEN '2010-05-01' AND '2010-05-31'
              and thread.CatID = 3
              group by datePost)daily on daily.daytime_daily=datepost



  where date(post.datePost) BETWEEN '2010-05-01' AND '2010-05-31'

  and thread.CatID = 3
  group by datePost, thehour

表示该时间范围内的平均每小时数，

select datePost as daytime,
  HOUR(timePost) as thehour, 
  count(TEXT) as thecount,
  hourly_average
  from post 
  inner join  thread on  post.threadID = thread.threadID 
  inner join (  select hour(timepost) as daytime_daily,
                count(TEXT)/count(distinct datePost) as hourly_average
              from post inner join thread on post.threadID = thread.threadID
              where date(post.datePost) BETWEEN '2010-05-01' AND '2010-05-31'
              and thread.CatID = 3
              group by datePost)daily on daily.daytime_daily=hour(timepost)



  where date(post.datePost) BETWEEN '2010-05-01' AND '2010-05-31'

  and thread.CatID = 3
  group by datePost, thehour

MySQL：计算每天每小时的平均帖子

1 个答案: