Question

我想在执行页面5秒后执行页面脚本

表示如果我访问http://localhost/form.php，则等待5秒钟，然后处理该页面的全部内容。

我的页面是

<?php
$con=mysqli_connect("localhost","root","","ex_smartcard2013");

if (mysqli_connect_errno())
  { 
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
  }

$result3 = mysqli_query($con,"SELECT  id,name,course,amount FROM fess order by id desc limit 1");
while($row = mysqli_fetch_array($result3))
{ 
if($row['name'])
{ 

$id = $row['id'];
$name = $row['name'];
$course = $row['course'];
$amount = $row['amount'];

}
}
?>
<div style="display:none;">
<iframe id="ponyo_frame" name="ponyo_frame"></iframe>
<div class="ss-form"><form action="https://docs.google.com/forms/d/1IDfOSwEcNYwvqxBHlGOTmPbZQrS7vr7Q1xw77UBVLUc/formResponse" method="POST" id="ss-form" target="ponyo_frame" onsubmit=""><ol style="padding-left: 0">

<input type="text" name="entry.1312370642" value="<?php echo $id; ?>" class="ss-q-short" id="entry_1312370642" dir="auto" title="">


<input type="text" name="entry.1082361902" value="<?php echo $name; ?>" class="ss-q-short" id="entry_1082361902" dir="auto" title="">



<input type="text" name="entry.234382219" value="<?php echo $course; ?>" class="ss-q-short" id="entry_234382219" dir="auto" title="">


<input type="text" name="entry.1270326869" value="<?php echo $amount; ?>" class="ss-q-short" id="entry_1270326869" dir="auto" title="">


</div></div><script type="text/javascript">
document.getElementById("ss-form").submit();
</script>
</div>

Answer 1

PHP是服务器端，它处理请求，发送响应并停止，每个新请求都是新的程序实例，当您查看页面时，没有PHP正在运行，它只在您“请求”时运行“内容。

你必须使用JavaScript来做客户端：

<script type="text/javascript">
    setTimeout(function() {
        //some ajax call that will call another php script and trigger your MySQL query
        ...
    }, 10000);
</script>

如果您需要获得有关如何运行Ajax查询的说明，请查看JQuery http://api.jquery.com/jQuery.ajax/（文档）http://learn.jquery.com/ajax/（教程）

Answer 2

例如：

<body>
   <div class="empty"></div>
</body>
<script>
    $(document).ready(function(){
       // The code throw javascript to render the page html
       $('.empty').append('
            <form>
                <input type="text" value="Type Here" />
            </form>
       ');
    }).delay(5000);
</script>

这不是一个好习惯，但它会帮助你做你想做的事您还需要添加jquery

页面调用后10秒后运行脚本

2 个答案: