Question

在以下代码中，我尝试在arrayDoctors中添加用户选择的名称，比如A,B，然后我将其添加到selectedDoctors数组。但是，第二次选择医生C,D并将其添加到selectedDoctors数组时，它会将之前的对象A,B替换为C和D。

- (void)doneDoctorSelection:(id)sender
{
   [pop3 dismissPopoverAnimated:YES];
   NSString *str = [arrayDoctors objectAtIndex:0];
   NSString *str1 = [str stringByAppendingString:[NSString stringWithFormat:@" + %d",arrayDoctors.count-1]];

   if([arrayDoctors count] == 1)
    lblDoctor.text = str;
   else
      lblDoctor.text = str1;

   [selectedDoctors addObject:arrayDoctors];
   [selectedDoctorIdList addObject:arrayDoctorsId];

   NSLog(@"selectedDoneDoctors %@ ",selectedDoctors);

}

我做错了什么？

Answer 1

阿!!终于找到了解决方案。我在将新值放入其中之前从arrayDoctors中删除了对象，并且我已经在viewDidLoad方法中对其进行了初始化。所以发生的事情就是我做了[selectedDoctors addObject：arrayDoctors];第二次它在第一个位置替换相同的对象，因为它使用相同的内存位置。解决方案是创建一个临时对象。以下是更改后的代码。

- (void)doneDoctorSelection:(id)sender
{
   [pop3 dismissPopoverAnimated:YES];
   NSString *str = [arrayDoctors objectAtIndex:0];
   NSString *str1 = [str stringByAppendingString:[NSString stringWithFormat:@" + %d",arrayDoctors.count-1]];

   NSMutableArray *tempDoctor = [[NSMutableArray alloc]initWithArray:arrayDoctors];
   NSMutableArray *tempDocorId = [[NSMutableArray alloc]initWithArray:arrayDoctorsId
                               ];

   if([arrayDoctors count] == 1)
       lblDoctor.text = str;
   else
       lblDoctor.text = str1;

   NSLog(@"Before Adding %@ ",selectedDoctors);

   [selectedDoctors addObject:tempDoctor];
   [selectedDoctorIdList addObject:tempDocorId];

   //[selectedDoctors addObjectsFromArray:arrayDoctors];
   //[selectedDoctorIdList addObjectsFromArray:arrayDoctorsId];

   NSLog(@"selectedDoneDoctors %@ ",selectedDoctors);

}

Thanx指责我正确的方向。

Answer 2

而不是这部分

NSMutableArray *tempDoctor = [[NSMutableArray alloc]initWithArray:arrayDoctors];

[selectedDoctors addObject:tempDoctor];

您可以使用

[selectedDoctors addObject:[arrayDoctors mutableCopy]];

addObject替换以前的值

2 个答案: