Question

我正在用滑块编写游戏。为了将游戏从解决状态中洗牌，我想定期反复调用pushRandomPiece以在视觉上改变游戏。

我想首先使用dispatch_after，但我对触发日期有疑问：

这有效：

-(void)shuffle {
    for (int i=0; i<50;i++)
    [self performSelector:@selector(pushRandomPiece) withObject:nil afterDelay:i*0.50*2];
}

pushRandomPiece中两个连续调用之间的差异几乎总是等于一秒。

但这不起作用：

-(void)shuffle {
    for (int i=0; i<50;i++)
//        [self performSelector:@selector(pushRandomPiece) withObject:nil afterDelay:i*0.50*2];
        dispatch_after(dispatch_time(DISPATCH_TIME_NOW, i*NSEC_PER_SEC*0.5*2), dispatch_get_main_queue(), ^{ [self pushRandomPiece]; });
}

以下是连续通话之间的时差：

2013-10-01 11:02:53.147 SlidingPuzzle[2006:60b] diff= 1.077376
2013-10-01 11:02:54.262 SlidingPuzzle[2006:60b] diff= 1.111863
2013-10-01 11:02:55.335 SlidingPuzzle[2006:60b] diff= 1.070456
2013-10-01 11:02:56.455 SlidingPuzzle[2006:60b] diff= 1.117381
2013-10-01 11:02:57.542 SlidingPuzzle[2006:60b] diff= 1.084070
2013-10-01 11:02:58.655 SlidingPuzzle[2006:60b] diff= 1.110574
2013-10-01 11:02:59.757 SlidingPuzzle[2006:60b] diff= 1.098654
2013-10-01 11:03:00.862 SlidingPuzzle[2006:60b] diff= 1.103132
2013-10-01 11:03:01.956 SlidingPuzzle[2006:60b] diff= 1.091535
2013-10-01 11:03:03.050 SlidingPuzzle[2006:60b] diff= 1.090532
2013-10-01 11:03:04.160 SlidingPuzzle[2006:60b] diff= 1.107981
2013-10-01 11:03:04.164 SlidingPuzzle[2006:60b] diff= 0.000982
2013-10-01 11:03:06.354 SlidingPuzzle[2006:60b] diff= 2.187945
2013-10-01 11:03:06.357 SlidingPuzzle[2006:60b] diff= 0.000862
2013-10-01 11:03:08.498 SlidingPuzzle[2006:60b] diff= 2.139442
2013-10-01 11:03:08.501 SlidingPuzzle[2006:60b] diff= 0.000805
2013-10-01 11:03:10.750 SlidingPuzzle[2006:60b] diff= 2.246749
2013-10-01 11:03:10.753 SlidingPuzzle[2006:60b] diff= 0.000839

以下是使块移动的方法：

-(void) pushRandomPiece {
    NSSet * s = [self freeBlocks];
    int n = [s count];
    int piece = arc4random_uniform(n);
    Piece * p = [[s allObjects] objectAtIndex:piece];
    dispatch_async(dispatch_get_main_queue(), ^{
        [self pushPiece:p];
    });
}

Answer 1

dispatch_after仅在您指定的时间后将您的块添加到队列中。如果队列为空，则可以在添加到队列后立即运行块。否则，它可能会在运行之前在队列中停留一段时间 - 等待其他任务完成。

dispatch_after与performSelector afterDelay

1 个答案: