获取不在file2中的file1行

Question

我有两个很长但已排序的文件。如何获取不在第二个文件中的第一个文件的所有行？

文件1

0000_aaa_b
0001_bccc_b
0002_bcc <------ file2 have not that line
0003_aaa_d
0006_xxx
...

file2的

0000_aaa_b
0001_bccc_b
0003_aaa_d
0006_xxx
...

Answer 1

这是comm命令的用途：

$ comm -3 file1 file2
0002_bcc

来自man comm：

DESCRIPTION

   Compare sorted files FILE1 and FILE2 line by line.

   With  no  options,  produce  three-column  output.  Column one contains
   lines unique to FILE1, column two contains lines unique to  FILE2,  and
   column three contains lines common to both files.

   -1     suppress column 1 (lines unique to FILE1)

   -2     suppress column 2 (lines unique to FILE2)

   -3     suppress column 3 (lines that appear in both files)

Answer 2

只需对它们运行diff：

diff -c file1 file2

-c（用于“上下文”）标记仅显示不同的行，每行包含两行。