MOD运算符在where子句中

Question

如果在MOD子句中使用WHERE获取无效数字异常，则希望根据ID更新偶数行或奇数行。

update employee  set respstr1 = 'EP' where mid = 7246 and (mod(id/2) = 1)

Answer 1

mod的正确语法是

mod(id,2)

Answer 2

试

update employee  set respstr1 = 'EP' where mid = 7246 and (mod(id,2) = 1)

有关详细信息，请参阅以下链接 http://docs.oracle.com/cd/B19306_01/server.102/b14200/functions088.htm